The speed of the target with the bullet lodged in it is 5.6 m/s.
<h3>What is speed?</h3>
This is the rate of change of distance.
To calculate the speed of the target and the bullet lodged, we use the formula below.
Formula:
- V = mu/(m+M)............. Equation 1
Where:
- V = Speed of the target and the bullet
- m = mass of the bullet
- M = mass of the target
- u = Initial speed of the target
From the question,
Given:
- m = 0.04 kg
- u = 1400 m/s
- M = 9.96 kg
Substitute these values into equation 1
- V = (0.04×1400)/(0.04+9.96)
- V = 56/10
- V = 5.6 m/s
Hence, the speed of the target with the bullet lodged in it is 5.6 m/s.
Learn more about speed here: brainly.com/question/6504879
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A sample of water is taken and kept in a beaker in a freezer at a constant temperature of 0°C. If the system is at dynamic equilibrium, which of these statements is true?
C. is the only double reaction here given that a double replacement reaction involves two compounds that exchange previous components, and C is the only solution with two compounds present
