What do we call an object displaced by an unbalanced Force,
Accelerated object,
And we also know that,
Due to acceleration, An object displaces.
But I'll use Newton's 1st law to prove it,
Which is, An object will remain in rest or in uniform motion until it is compelled by an external Force.
As per the his law,
The cat will remain on the dashboard of that moving car until it is compelled by Air Force (external Force).
!! Hope It Helps !!
Answer:
a) total moment of inertia is 1359.05 kg m^2
b) angular acceleratio is 0.854rad/sec^2
Explanation:
Given data:
m1=6.9 kg
L=4.88 m
m2=34.5 kg
R=1.22 m
we klnow that moment of inertia for rod is given as
J1=(1/12) ×m×L^2

moment of inertia for sphere is given as
J1=(2/5) ×m×r^2

As object rotates around free end of rod then for sphere the axis around what it rotates is at a distance of d2=L+R
For rod distance is d1=0.5*L
By Steiner theorem
for the rod we get 

for the sphere we get 

And the total moment of inertia for the first case is

b) F=476 N
The torque for system is given as

where a is angle between Force and distance d
and where d represent distance from rotating axis.
In this case a = 90 degree

M=476*2.44 = 1161.44 Nm
The acceleration is calculated as

= 0.854 rad/sec^2
Answer:
a) The student feel light
b) Nbottom = 758 N
c) N'top= 236 N
d) N'bottom= 1055 N
Explanation:
a) W= 659N , Ntop= 560N
W > Ntop ---> Student feel less weight
b) Top:
∑F= W - Ntop = m.v²/R
m.v²/R = 659N - 560 N = 99 N
Bottom:
∑F= Nbottom- W = m.v²/R
Nbottom= W + m.v²/R = 659N + 99 N = 758N
c) W= 659 N , Ntop= 560 N , v'=2.v
N'top= ?
∑F= W - N'top = m.v'²/R
N'top= W - 4.m.v²/R
N'top = 659 N - 4. 99 N = 263 N
d) N'bottom = ?
∑Fbottom= N'bottom- W = m.v'²/R
N'bottom = W + 4.m.v²/R = 659 N + 4. 99 N = 1055 N
You will probably be fit to be a elementary school teacher
Answer:
Mechanical
Explanation:
The tank is at rest. And energy of any substance at rest is known as potential energy.
Now, in forms of energy, potential energy is a type of mechanical energy.
Thus, the correct option is mechanical Energy.