Answer:
If it was only 10 degrees the seasonal changes would lessen and vise versa for 50. meaning the seasonal changes would become more extreme
Explanation:
Answer:
Hey
The rope isn't moving because each boy is pulling with the same force on opposite ends. That being said the bot pulling force is balanced.
Inside the rope are molecules connecting the whole thing together. The force they exert on each other must be equal because they aren't moving but are still exerting forces
That's a formula that shows the relationship between three quantities ...
weight, mass, and acceleration. If you know any two of them, then you
can use this formula to find the one you don't know.
Examples:
==> I have a rock with 2 kilograms of mass.
The gravitational acceleration on Earth is 9.8 m/s² .
How much does my rock weigh on Earth ?
Weight = (mass) x (grav acceleration)
= (2 kg) x (9.8 m/s²)
= 19.6 newtons
(about 4.41 pounds)
==> My brother weighs 770 newtons (about 173 pounds) on Earth.
What is his mass ?
Weight = (mass) x (grav acceleration)
770 newtons = (mass) x (9.8 m/s²)
Divide each side
by 9.8 m/s²: 770 newtons / 9.8 m/s² = mass
78.57 kilograms = mass
==> When I went to the Moon, I took along my 2-kilogram rock.
I weighed my rock on the Moon.
It weighs 3.25 newtons (about 0.73 pound) there.
What is the gravitational acceleration on the Moon ?
Weight = (mass) x (grav acceleration)
3.25 newtons = (2 kg) x (acceleration)
Divide each side
by 2 kilograms: (3.25 newtons)/(2 kg) = acceleration
1.63 m/s² = grav acceleration on the Moon
Answer: C = Q/4πR
Explanation:
Volume(V) of a sphere = 4πr^3
Charge within a small volume 'dV' is given by:
dq = ρ(r)dV
ρ(r) = C/r^2
Volume(V) of a sphere = 4/3(πr^3)
dV/dr = (4/3)×3πr^2
dV = 4πr^2dr
Therefore,
dq = ρ(r)dV ; dq =ρ(r)4πr^2dr
dq = C/r^2[4πr^2dr]
dq = 4Cπdr
FOR TOTAL CHANGE 'Q', we integrate dq
∫dq = ∫4Cπdr at r = R and r = 0
∫4Cπdr = 4Cπr
Q = 4Cπ(R - 0)
Q = 4CπR - 0
Q = 4CπR
C = Q/4πR
The value of C in terms of Q and R is [Q/4πR]
