Answer:
2400 J
Explanation:
Latent heat: This is also called hidden heat, it is the heat that is not detectable by the thermometer.
From the question,
Q = cm.................. Equation 1
Where Q = Energy, c = specific latent heat of the liquid, m = mass of the liquid.
Given: c = 4000 J/kg, m = 600 g =( 600/1000) kg = 0.6 kg
Substitute these values into equation 1
Q = 4000×0.6
Q = 2400 J
Hence the energy required is 2400 J
The net force acting on the refrigerator is 400 N to the right.
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FURTHER EXPLANATION</h3>
The net force or resultant force is the sum of all the forces acting on a body or an object in x and y axes.
- Forces along the y-axis The forces that usually act on an object vertically (in the y-axis) are: gravitational force which is a downward force and the normal force which is an upward (perpendicular) force exerted by a surface on an object resting above it that keeps the object from falling.
- Forces along the x-axis These include the force or forces applied to cause a left or right motion of an object along the horizontal plane (called the Applied Force) and the force that opposes the motion or friction.
In this problem the forces acting on the x and y - axes can be determined:
Along the x-axis:
- gravitational force = -1960 N
- normal force = +1960 N
- Net force = -1960 N + 1960 N = 0
The gravitational force is the weight of the object obtained by multiplying the mass of the object (in kg) with the acceleration due to gravity, 9.8 m/s^2. It is given a negative (-) sign to indicate that it is a downward force.
Since the object is not falling through the surface, it can be assumed that the gravitational force and normal force are balanced. Hence, the size of the normal force is the same as the gravitational force but with the opposite direction indicated by the + sign for an upward force.
The forces along the x-axis are balanced (i.e. net force is zero) so the object neither moves upward or downward.
Along the y-axis
- applied force = +400 N
- friction = 0
- Net force = +400 N + 0 = +400 N
The applied force is +400 N. It is given a + sign to indicate that its direction is to the right.
The friction, as mentioned in the problem, is set to zero or "turned off".
The net force along the y-axis is +400. The forces are unbalanced so the object will move to the right as force is applied to it.
<h3>LEARN MORE</h3>
Keywords: net force, resultant force
The total energy stored in the capacitors is determined as 2.41 x 10⁻⁴ J.
<h3>What is the potential difference of the circuit?</h3>
The potential difference of the circuit is calculated as follows;
U = ¹/₂CV²
where;
- C is capacitance of the capacitor
- V is the potential difference
For a parallel circuit the voltage in the circuit is always the same.
The energy stored in 2.5 μf capacitor is known, hence the potential difference of the circuit is calculated as follows;
U = ¹/₂CV²
2U = CV²
V = √2U/C
V = √(2 x 1.8 x 10⁻⁴ / 2.5 x 10⁻⁶)
V = 12 V
The equivalent capacitance of C1 and C2 is calculated as follows;
1/C = 1/C₁ + 1/C₂
1/C = (1)/(0.9 x 10⁻⁶) + (1)/(16 x 10⁻⁶)
1/C = 1,173,611.11
C = 1/1,173,611.11
C = 8.52 x 10⁻⁷ C
The total capacitance of the circuit is calculated as follows;
Ct = 8.52 x 10⁻⁷ C + 2.5 x 10⁻⁶ C
Ct = 3.35 x 10⁻⁶ C
The total energy of the circuit is calculated as follows;
U = ¹/₂CtV²
U = ¹/₂(3.35 x 10⁻⁶ )(12)²
U = 2.41 x 10⁻⁴ J
Learn more about energy stored in a capacitor here: brainly.com/question/14811408
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Answer:
31.8 × 10⁻⁴ J = 3.18 mJ
Explanation:
We know the intensity I of a wave is I = P/A where P = power and A = area = 0.500 m²
The intensity of an electromagnetic wave is also equal to I = E₀²/μ₀c
where E₀ = maximum electric field strength = √2E where E = rms value of electric field = 0.0200 N/C, μ₀ = 4π × 10⁻⁷ H/m ,c = 3 × 10⁸ m/s
P/A = E₀²/μ₀c = 2E²/μ₀c
P = 2E²A/μ₀c = 2 × (0.02 N/C)² × 0.5 m²/(4π × 10⁻⁷ H/m × 3 × 10⁸ m/s)
= 1.06 × 10⁻⁴ W = 0.106 mW
Since P = E/t where E = Energy and t = time
E = Pt with t = 30 s
E = 1.06 × 10⁻⁴ W × 30 s = 31.8 × 10⁻⁴ J = 3.18 mJ
So the wave carries 3.18 mJ of energy through the window in 30 s
Combustion, also known as burning, is the basic chemical process of releasing energy from a fuel and air mixture. In an internal combustion engine (ICE), the ignition and combustion of the fuel occurs within the engine itself. The engine then partially converts the energy from the combustion to work.
