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neonofarm [45]
3 years ago
7

How does communication relate to measuring? cite examples​

Physics
1 answer:
Basile [38]3 years ago
7 0
At intervals to track attitudes regular measurement helps communicators to gauge the ever-shifting feelings and attitudes within an organization and to tailor messages to make sure they are appropriate to their audiences.
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The difference in potential between the accelerating plates of a TV set is about 24 kV. The distance between these plates is 1.5
ryzh [129]

Answer:

So electric field between the plates will be equal to 1600\times 10^3KN/C

Explanation:

We have given potential difference between accelerating plates = 24 KV = 24000 volt

Distance between the plates d = 1.5 cm = 0.015 m

We know that potential difference is given by V = Ed, here E is electric field and d is distance between plates

So 24000=E\times 0.015

E = 1600000 N/C = 1600\times 10^3KN/C

So electric field between plates will be equal to 1600\times 10^3KN/C

7 0
3 years ago
A defibrillator containing a 18.4 μF capacitor is used to shock the heart of a patient by holding it to the patient's chest. Jus
gregori [183]

Answer:

The energy E is 1603.008 J.

Explanation:

Given that,

Capacitor = 18.4 μF

Voltage = 13.2 kV

We need to calculate the energy

Using formula of energy

E=W=\int{Q}\ dV.....(I)

We know that,

Q=CV

Put the value of Q in equation (I)

E=\int{CV}dV

On integration

E=\dfrac{CV^2}{2}

Put the value into the formula

E=\dfrac{18.4\times10^{-6}\times(13.2\times10^{3})^2}{2}

E=1603.008\ J

Hence, The energy E is 1603.008 J.

3 0
4 years ago
Velocity vectors point in the same direction as displacement?
liq [111]

Explanation:

You walk 53m to the north, then you turn 60° to your right and walk another 45m. Determine the direction of your displacement vector. Express your answer as an angle relative to east

8 0
3 years ago
Read 2 more answers
The vertical normal stress increase caused by a point load of 10 kN acting on the ground surface at a point 1m vertically below
Tomtit [17]

Answer:

(b) 4.775 kN

Explanation:

see the attached file

8 0
3 years ago
A proton moving along the positive x-axis enters a uniform magnetic field which is directed along the
SSSSS [86.1K]

Answer: The force acting on the proton of charge ​1.5 x10-19 C moving with velocity 1.5 x10-19 C under the influence of a magnetic field of 0.7 T will be 3.15×10^-13 N.

Explanation: To find the answer we need to know more about the Lorentz magnetic force.

<h3>What is the Lorentz magnetic force acting on the proton?</h3>
  • Consider a proton of charge q moving with a velocity v in a magnetic field, then the Lorentz magnetic force exerted on the proton can be expressed as,

                                  F= q (v× B)

                               F= qvBsin\alpha  where, \alpha is the angle between v and B.

  • In the question, it is given that,

                                B=0.7 T\\q=1.5*10^{-19}C\\v= 3*10^{6}m/s.\\\alpha =90 degree.\\ because, from the question it is clear that the proton is moving along x axis and the magnetic field is along the y axis.

  • Thus, we can find the force acting on the proton as,

                      F=qvBsin\alpha =1.5*10^{-19}C*3*10^6 m/s*0.7T*sin (90)\\F=3.15*10^{-13}N

Thus, we can conclude that the Lorentz force acting on the proton will be 3.15×10^-13 N.

Learn more about the Lorentz magnetic force here:

brainly.com/question/28047923

#SPJ1

6 0
2 years ago
Read 2 more answers
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