Balanced forces do not cause a change in motion. When balanced forces act on an object at rest, the object will not move. If you push against a wall, the wall pushes back with an equal
The tension force being supplied by the rope is 245 N.
<h3>What is tension force?</h3>
- Tension force is the force exerted on a rope or cord due to the weight of an object suspended from it.
The tension force on the given rope due to the weight of the lamp hanging from the rope is calculated by applying Newton's second law of motion as shown below;
T = mg
where;
- m is the mass = 25 kg
- g is acceleration due to gravity = 9.8 m/s²
T = 25 x 9.8
T = 245 N
Thus, the tension force being supplied by the rope is 245 N.
Learn more about tension force here: brainly.com/question/2008782
Answer:
Explanation:
As we know that the rate of heat transfer due to temperature difference is given by the formula
here we know that
A = 4 m x 7 m
thickness = 30 cm
temperature difference is given as
now we have
Answer:
The number of paces it would take to get to the Moon is 213,555,556 paces
Explanation:
The given length of Mr Galan's paces = 1.8 m/pace
The distance from the Earth to the Moon is, 384,400 km = 384,400,000 m
Therefore, the number of paces, "n", it would take to get to the Moon from the Earth is given as follows;
n = (The distance from the Earth to the Moon)/(The length of each Mr Galan's paces)
∴ n = 384,400,000 m/(1.8 m/pace) = 213,555,556 paces
The number of paces it would take to get to the Moon = n = 213,555,556 paces
Answer:
It would take the object 5.4 s to reach the ground.
Explanation:
Hi there!
The equation of the height of a free-falling object at any given time, neglecting air resistance, is the following:
h = h0 + v0 · t + 1/2 · g · t²
Where:
h = height of the object at time t.
h0 = initial height.
v0 = initial velocity.
g = acceleration due to gravity (-32.2 ft/s² considering the upward direction as positive).
t = time
Let´s supose that the object is dropped and not thrown so that v0 = 0. Then:
h = h0 + 1/2 · g · t²
We have to find the time at which h = 0:
0 = 470 ft - 1/2 · 32.2 ft/s² · t²
Solving for t:
-470 ft = -16.1 ft/s² · t²
-470 ft / -16.1 ft/s² = t²
t = 5.4 s
