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4 years ago

A machine can multiply forces for

Physics

1 answer:

Degger [83]4 years ago

4 0

A greater effect.

Hope this helps!

-Payshence

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Which is a compound? Select one: a. O2 b. Cl2 c. Kr d. CuF2

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CuF2 is the Answer if it’s wrong let me know

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4 years ago

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Strategic control tends to stifle creativity, which causes poor results.<br> True<br> False

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3 years ago

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A billiard ball with a mass of 1.5kg is moving at 25m/s and strikes a second ball with a mass of 2.3 kg that is motionless. Find

aliya0001 [1]

Answer:

The velocity of the second ball after the collision will be 16.3 m/s.

Step-by-Step Explanation:

Law of conservation of momentum states that the total momentum of an isolated remains the same before and after the collision.

Let: mass of the first ball = m1 = 1.5 kg

mass of the second ball = m2 = 2.3 kg

Momentum before the collision:

velocity of the first ball = v1 = 25 m/s

velocity of the second ball = v2 = 0 m/s

[tex] Initial momentum = m1v1 + m2v2 = 1.5*25 + 2.3*0 = 37.5 kgm/s [\tex]

Momentum after the collision:

velocity of the first ball = v1 = 0 m/s

velocity of the second ball = v2 = x

[tex]momentum after the collision= m1v1 + m2v2 = 1.5*0 + 2.3*x = 2.3*x[\tex]

According to law of conservation of momentum:

Initial momentum = Momentum after collision

37.5 = 2.3*x

⇒ x = 37.5/2.3

x = 16.3 m/s

4 0

3 years ago

At room temperature, an oxygen molecule, with mass of 5.31x10^-26kg , typically has a kinetic energy of about 6.21x10^-21J. How

den301095 [7]

Answer:

V=483.63 m/s

Explanation:

Given that

mass ,m= 5.31 x 10⁻²⁶ kg

Kinetic energy KE= 6.21 x 10⁻²¹ J

As we know that the kinetic energy of the mass m with moving velocity V given as

$KE=\dfrac{1}{2}mV^2$

Now by putting the values

$6.21\times 10^{-21}=\dfrac{1}{2}\times 5.31\times 10^{-26}\times V^2$

$V^2=\dfrac{2\times 6.21\times 10^{-21}}{5.31\times 10^{-26}}$

$V^2=233898.30$

$V=\sqrt{233898.30}\ m/s$

V=483.63 m/s

Therefore the velocity of the molecule at the room temperature will be 483.63 m/s.

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4 years ago

A uniform electric field, with a magnitude of 370 N/C, is directed parallel to the positive x-axis. If the electric potential at

dem82 [27]

Answer:

$\Delta U = 0.2072 J$

Explanation:

Potential difference between two points in constant electric field is given by the formula

$\Delta V = E.\Delta x$

here we know that

$E = 370 N/C$

also we know that

$\Delta x = 2.1 - 1.9 = 0.2 m$

now we have

$\Delta V = 370 (0.2) = 74 V$

now change in potential energy is given as

$\Delta U = Q\Delta V$

$\Delta U = (2.80 \times 10^{-3})(74)$

$\Delta U = 0.2072 J$

3 0

4 years ago