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Anika [276]
3 years ago
13

Which of the following apply to diffusion. Select all that apply. Solids can diffuse in liquids. Liquids can diffuse in liquids.

It is the process of intermingling atoms from one substance into another. Gas molecules are very close together and diffuse slowly. A solid cannot diffuse in to another solid.
Chemistry
2 answers:
inn [45]3 years ago
6 0

Explanation:

Diffusion is defined as the ability of a substance to spread readily. So, when molecules of a matter have high kinetic energy then they tend to spread readily because of more number of collisions.

In solids, molecules have strong intermolecular forces of attraction so they do not have spaces in between them. Hence, solids are not able to diffuse in solids.

Solids are able to diffuse into liquids as liquids have spaces in between their particles.

For example, NaCl is soluble in water.

Thus, we can conclude that the following apply to diffusion.

  • Solids can diffuse in liquids.
  • Liquids can diffuse in liquids.
  • It is the process of intermingling atoms from one substance into another.
  • A solid cannot diffuse in to another solid.
e-lub [12.9K]3 years ago
3 0

Correct answers are:

  • Solids can diffuse in liquids. Think of a sugar cube sitting at the bottom of a cup of tea.
  • Liquids can diffuse in liquids. Think of a drop of food colouring in water
  • It is the process of intermingling atoms from one substance into another.

The other answers are <em>incorrect</em> because:

  • Gas molecules are far apart and diffuse rapidly.  
  • A solid can diffuse into another solid. Pure lead can diffuse into gold, and pure gold can diffuse into lead.
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Answer:

A.  Boyle's Law

B.  Charles' Law

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A mixture contains only nacl and al2(so4)3. a 1.45 g sample of the mixture is dissolved in water, and an excess of naoh is added
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When mixture of NaCl and Al₂(SO₄)₃ is allowed to react with excess NaOH, only Al₂(SO₄)₃ reacts with it and NaCl does not react with NaOH due to presence of common ion (Na⁺). On reaction gelatinous precipitate of aluminium hydroxide [Al(OH)₃] is produced.  The balanced chemical reaction is represented as-

Al₂(SO₄)₃ + 6NaOH → 2Al(OH)₃ + 3Na₂SO₄

On this reaction, 0.495 g = 0.495/78 moles =6.346 X 10⁻³ moles of Al(OH)₃.

As per balanced reaction, two moles of Al(OH)₃ is produced from one mole Al₂(SO₄)₃. So, 6.346 X 10⁻³ moles of Al(OH)₃ is produced from (6.346 X 10⁻³)/2 moles=3.173 X 10⁻³ moles of Al₂(SO₄)₃= 3.173 X 10⁻³ X 342 g of Al₂(SO₄)₃=1.085 g of Al₂(SO₄)₃.

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7 0
3 years ago
What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha
sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

<u>Given:</u>

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

<u>To determine:</u>

The mean free path, λ

<u>Calculation:</u>

The mean free path is related to the collision cross section by the following equation:

\lambda =\frac{1}{n\sigma }------(1)

where n = number density

n = \frac{P}{kT}-----(2)

Substituting for P, k and T in equation (2) gives:

n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\  m^{3}

Next, substituting for n and σ in equation (1) gives:

\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m

6 0
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