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Akimi4 [234]
3 years ago
5

Find the values of a and b in the rhombus below.

Mathematics
2 answers:
loris [4]3 years ago
5 0

Hello,

b = 26°
( 26° × 2 ) + 2a = 360°
52° + 2a = 360°
2a = 360° - 52° = 308°
a = 308° / 2 = 154°

ioda3 years ago
3 0
Since,ABCD is a rhombus =>diagonals bisect each other at 90
b=26. (In a rhombus all sides are parallel)
To find a
In triangle, ABD
Angel ADB=26. ( base angle ppty)
=> Angel a=26+26+a=180. ( angle sum ppty of a triangle)
=>a=180-52=128
Hope this helps u...!!

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What single decimal multiplier would you use to increase by 18% followed by a<br> 12% decrease?
ValentinkaMS [17]

Answer:

The single decimal multiplier used to increase by 18% followed by a  12% decrease is 0.21.

Step-by-step explanation:

Let 'x' be the number

As first the number has to be increased by 18%

so

Step 1: write the percentage '18%' in decimal form

18% = 0.18    

Step 2: For percentage increases: add the decimal to 1

1 + 0.18 = 1.18    

Step 3: Multiply the number x by the multiplier, found in Step 2

x × 1.18 = 1.18x

<u><em>NEXT WE HAVE TO DECREASE 1.18x by 12%</em></u>

Apply the same method but with a number 1.18x

  • Write the percentage '12%' in decimal form

12% = 0.12

  • For percentage decreases: subtract the decimal to 1

1 - 0.18 = 0.18

  • Multiply the number 1.18x by the multiplier, found in Previous step

1.18x × 0.18 = 0.21x

Therefore, the single decimal multiplier used to increase by 18% followed by a  12% decrease is 0.21.

7 0
3 years ago
Find the area of each sector shown (the shaded section)
mihalych1998 [28]

Answer:

The area of the sector (shaded section) is 29.51 m^{2}.

Step-by-step explanation:

Area of a sector = (θ ÷ 360) \pir^{2}

where θ is the central angle of the sector, and r is the radius of the circle.

From the diagram give, diameter of the circle is 26 m. So that;

r = \frac{diameter}{2}

 = \frac{26}{2} = 13 m

θ = 360 - (180 + 160)

  = 360 - 340

  = 20^{o}

Thus,

area of the given sector = \frac{20}{360} x \frac{22}{7} x (13)^{2}

                                        = \frac{20}{360} x x \frac{22}{7} x 169

                                         = 29.5079

The area of the sector (shaded section) is 29.51 m^{2}.

4 0
3 years ago
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