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3 years ago

The transfer of valence electrons produces negatively charged ions called anions. True or False?

1 answer:

6 0

True and false. When a metal atom, for example, transfers its electrons (loses them) it become positively charged (cation). While non-metal atoms gain electrons, they become negatively charged (anions).

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The hormone, thyroxine is secreted by the thyroid gland, and has the formula: c15h17no4i4. How many milligrams of iodine can be

Mandarinka [93]

Answer:

9.73 grams of iodine

Explanation:

First we calculate the molar mass of the tyroxine C₁₅H₁₇NO₄I₄:

M = 15 × 12 + 17 × 1 + 1 × 14 + 4 × 16 + 4 × 127 = 783 g/mole

The taking in account that 1 mole of tyroxine have 4 moles of iodine atoms (508 g) we devise the following reasoning:

if from 783 g of tyroxine we can extract 508 g of iodine

the from 15 g of tyroxine we can extract X g of iodine

X = (15 × 508) / 783 = 9.73 grams of iodine

4 0

4 years ago

Identify Periodic Table

Anarel [89]

A)poor metals
B)Nobel gases
C)metalloids
D)transition metals
E)alkali metals

3 0

4 years ago

Read 2 more answers

Malic acid, C4H6O5, has been isolated from apples. Because this compound reacts with 2 molar equivalents of base, it is a dicarb

Flura [38]

Answer and explanation:

The attached figure shows five different structures for the chemical formula C4H5O5, but only one of these structures represent the malic acid.

Malic acid is a dicarboxylic acid, this means malic acid has two

-COOH groups. Also, malic acid is a secundary alcohol, which means it has a R2-C-OH group.

-Structure A has two carboxylic groups, but it doesn´t have a secundary alcohol.

-Structure B doesn´t have any caborxylic group.

-Structure C has two carboxylic groups and it is a secundary alcohol. Structure C is the Malic acid

4 0

3 years ago

How many grams of H2O are produced when 35.0 g of NaOH reacts with 17.5 g of CO,?

zhenek [66]

Answer:

2NaOH + CO2 -> Na2CO3 + H2O

1) Find the moles of each substance

$\eq n(NaOH)=\frac{35.0}{22.99+16.00+1.008\\}\ =\frac{35.0}{39.998} \ = 0.8750437522 moles\\n(CO_{2} ) = \frac{17.5}{12.01+32.00} = \frac{17.5}{44.01} = 0.3976369007 moles\\$

2) Determine the limitting reagent

$\\NaOH = \frac{0.8750437522}{2} = 0.4375218761\\\\$

∴ Carbon dioxide is limitting as it has a smaller value.

3) multiply the limiting reagent by the mole ratio of unknown over known

n(H2O ) = 0.3976369007 × 1/2

= 0.1988184504 moles

4) Multiply the number of moles by the molar mass of the substance.

m = 0.1988184504 × (1.008 × 2 + 16.00)

= 0.1988184504 × 18.016

= 3.581913202 g

Explanation:

6 0

3 years ago

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Kaylis [27]

Answer:

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Explanation:

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4 0

3 years ago