Why do isotope decay
1 answer:
You might be interested in
Explanation:
It is known that for first order reaction, the equation is as follows.
t =
t = ?, K = rate constant = 79 1/s
Initial conc. of = 1.68
Decompose amount of = 52% of 1.68
=
= 0.8736
= 0.87
Now, = (1.68 - 0.87)
= 0.81
Therefore, calculate the value of t as follows.
t =
=
=
= s
=
Thus, we can conclude that 0.00921 s will be taken for 52% of the cyclobutane to decompose.