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mote1985 [20]
3 years ago
15

How many boxes of chopsticks shouldvthe manager order for a 30 day supply

Mathematics
1 answer:
marshall27 [118]3 years ago
7 0

He must order ...

           (33) x (the number of chopsticks he expects to use every day)
divided by
           (the number of chopsticks in each box) .

This gives him a 10% safety margin, just in case.
If he doesn't use them in the next 30 days, then he'll have some
ready to go for the next 30 days.

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Multiply special products (x+7)(x-7)
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Answer:

x^2-49

Step-by-step explanation:

first you have to combine like terms

//hope this helps//

8 0
3 years ago
F(x) = 3* + 10xand g(x) = 5x - 3, find (f - g) (x)
melisa1 [442]

Answer:

(f-g)(x)= (3x + 10) - (5x -3)

f-g = 3x + 10 - 5x + 3

f-g = -2x + 13

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2 years ago
The Wall Street Journal reported that Walmart Stores Inc. is planning to lay off employees at its Sam's Club warehouse unit. App
tatyana61 [14]

Answer:

a) \bar X = 52

Median = 55

b) Q_1= \frac{44+44}{2}=44

Q_3= \frac{57+60}{2}=58.5

c) Range = Max -Min = 69-36=33

d) s^2 =100.1429

s= \sqrt{100.143}=10.0071

e) Lower = Q_1 -1.5 IQR = 44-1.5(58.5-44) = 22.25

Upper = Q_1 +1.5 IQR = 44+1.5(58.5-44) = 65.75

A possible outlier would be the value of 69 since its above the upper limti for the boxplot.

Step-by-step explanation:

For this case we have the following dataset:

55 56 44 43 44 56 60 62 57 45 36 38 50 69 65

A total of 15 observations

Part a

We calculate the mean with the following formula:

\bar X = \frac{\sum_{i=1}^{15} X_i}{15}

And for this case we got \bar X = 52

For the median we ust need to order the data on increasing way like this:

36, 38,43,44,44,45,50,55,56,56,57,60,62,65,69

Since the number of observations is an odd number the median would be on the 8 position from the dataset ordered on this case:

Median = 55

Part b

In order to calculate the Q1 we need to select the following data:

36, 38,43,44,44,45,50,55

And the Q1 would be the average between the 4 and 5 positions like this:

Q_1= \frac{44+44}{2}=44

And for the Q3 we select these values:

55,56,56,57,60,62,65,69

And the Q3 would be the average between the 4 and 5 positions like this:

Q_3= \frac{57+60}{2}=58.5

Part c

The Range is defined as:

Range = Max -Min = 69-36=33

Part d

In order to calculate the sample variance we can use the following formula:

s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

And if we replace we got:

s^2 =100.1429

And the deviation is just the square root of the variance:

s= \sqrt{100.143}=10.0071

Part e

For this case we need to find the lower and upper limits for the boxplot given by:

Lower = Q_1 -1.5 IQR = 44-1.5(58.5-44) = 22.25

Upper = Q_1 +1.5 IQR = 44+1.5(58.5-44) = 65.75

A possible outlier would be the value of 69 since its above the upper limti for the boxplot.

4 0
4 years ago
Find the area of the figure
Yuri [45]

Answer:

A=153.94

Step-by-step explanation:

6 0
3 years ago
9y+y combining like terms
nignag [31]
10y..................................................................
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3 years ago
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