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3 years ago

If you mass 35kg on earth what will your mass be on the moon where gravity is 1/6 that of earths. PLZZZZ HElP NEED ASAP

Physics

1 answer:

abruzzese [7]3 years ago

4 0

Answer:

Mass will be same on moon as on Earth but weight will be one-sixth of Earth.

Explanation:

Mass of a body doesn't depend on gravity. Mass is a constant quantity. So, mass on moon will be same as mass on Earth.

But, the weight of a body depends on gravity as weight is given as:

$\textrm{Weight}=\textrm{mass}\times \textrm{acceleration due to gravity}$

Therefore, if $g$ is acceleration due to gravity on Earth, then weight on Earth is, $W_{E}=mg$

Now, gravity on moon is one-sixth of Earth. So, $g_{moon}=\frac{1}{6}g$

Therefore, weight of the body on moon is, $W_{moon}=mg_{moon}=m\times \frac{1}{6}g=\frac{1}{6}mg=\frac{1}{6}W_{E}$

Therefore, a body has same mass both on moon and Earth but weight on moon is one-sixth of the weight on Earth.

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The elastic portion of the downward-sloping straight-line demand curve lies:_______

zepelin [54]

Answer:

c. above the point of unit elasticity.

Explanation:

The elastic portion of the downward-sloping straight-line demand curve lies above the point of unit elasticity. Supply and demand are fundamental concept in economics. The demand curve shows how much of a good people will want at a different prices. The demands curves illustrates the intuition why people purchase a good for a lower price. For the demand curve, the price is always shown on the vertical axis and the demand curve is shown on the horizontal axis. Thus , the quantity demanded increases as the price gets lower. However, the price elasticity of the demand curve varies along the demand curve. This is because there is a key distinction between the gradient and the elasticity. The gradient which is the slope of the line is always the same in the demand curve but elasticity of the demand changes in the percentage of the quantity demand. Therefore, elasticity will vary along the downward-sloping straight - line demand curve. So, in a downward-sloping straight-line demand curve, the elastic portion is usually above the point of unit elasticity

7 0

3 years ago

projectile motion of a particle of mass M with charge Q is projected with an initial speed V in a driection opposite to a unifor

SIZIF [17.4K]

Answer:

Range, $R = MV²/2QE$

Explanation:

The question deals with the projectile motion of a particle mass M with charge Q, having an initial speed V in a direction opposite to that of a uniform electric field.

Since we are dealing with projectile motion in an electric field, the unknown variable here, would be the range, R of the projectile. We note that the electric field opposes the motion of the particle thereby reducing its kinetic energy. The particle stops when it loses all its kinetic energy due to the work done on it in opposing its motion by the electric field. From work-kinetic energy principles, work done on charge by electric field = loss in kinetic energy of mass.

So, [tex]QER = MV²/2{/tex} where R is the distance (range) the mass moves before it stops

Therefore {tex}R = MV²/2QE{/tex}

5 0

4 years ago

Calculate the electrical energy expended in a device across which the circuit voltage drops by 20.0 volts in moving a charge of

Inga [223]

Answer:

The answer is 80 Joules

Explanation:

Electrical energy = Q x V

Energy = 2 x 40

= 80

I just took the test and it was right :D

The correct answer is B.

I hope this helped! :D

6 0

4 years ago

A proton is released from rest at the origin in a uniform electric field that is directed in the positive x direction with magni

Vika [28.1K]

Explanation:

It is given that,

Electric field, $E=950\ N/C$

We need to find the change in the electric potential energy of the proton-field system when the proton travels to x = 2.5 m

From the conservation of energy, the loss in potential energy is equal to the gain in kinetic energy and kinetic energy is is equal to the work done.

$W=F\times x$

$W=q\times E\times x$

$W=1.6\times 10^{-19}\times 950\times 2.5$

$W=3.8\times 10^{-16}\ J$

So, the change in electric potential energy of the proton field system is $3.8\times 10^{-16}\ J$ . Hence, this is the required solution.

4 0

3 years ago

Football helmets are made with padding that helps reduce head injuries when a player collides with an object. Which best explain

sergeinik [125]

Football helmets that are made with padding are believed to have reduced head injuries especially when a player accidentally collides with an object. This is because the impact of the collision is decreased due to the padding that serves as a shock absorber.

4 0

3 years ago

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