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3 years ago

If you mass 35kg on earth what will your mass be on the moon where gravity is 1/6 that of earths. PLZZZZ HElP NEED ASAP

Physics

1 answer:

abruzzese [7]3 years ago

4 0

Answer:

Mass will be same on moon as on Earth but weight will be one-sixth of Earth.

Explanation:

Mass of a body doesn't depend on gravity. Mass is a constant quantity. So, mass on moon will be same as mass on Earth.

But, the weight of a body depends on gravity as weight is given as:

$\textrm{Weight}=\textrm{mass}\times \textrm{acceleration due to gravity}$

Therefore, if $g$ is acceleration due to gravity on Earth, then weight on Earth is, $W_{E}=mg$

Now, gravity on moon is one-sixth of Earth. So, $g_{moon}=\frac{1}{6}g$

Therefore, weight of the body on moon is, $W_{moon}=mg_{moon}=m\times \frac{1}{6}g=\frac{1}{6}mg=\frac{1}{6}W_{E}$

Therefore, a body has same mass both on moon and Earth but weight on moon is one-sixth of the weight on Earth.

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Approximately how much electrical energy does a 5-W lightbulb convert to radiant and thermal energy in one hour?

k0ka [10]

Answer:

18,000 j

Explanation:

the lightbulb dissipates 5W of power

P = ΔE / Δt

rearrange to solve for energy

ΔE = PΔt

P = 5W

t = 1 hour = 60 minutes = 3600 seconds

ΔE = 5 * 3600

ΔE = 18000 J

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3 years ago

A 100-newton box is placed on a table. The table can exert a maximum normal force of 80 newtons. What will happen to the box?

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4 years ago

A body is at equilibrium under the action of three forces. One force is 10N acting due east and one is 5N in the direction 60° n

olchik [2.2K]

Answer:

If the body is in equilibrium the two forces add up and the third is the opposite of the resultant.

F(1x)=F(1)=10 N

F(2x)=F(2)cos60=5•0.5=2.5 N

F(2y) =F(2)sin60 = 5•0.866= 4.33 N

F(3x) =- F(x)=- (10+2.5 )= -12.5 N

F(3y) =- F(2y)= - 4.33 N

F(3) = sqrt{ F(3x)²+F(3y)²} =13.23 N

tan φ = F(3y)/F(3x) =4.33/12.5=0.364

φ = 19.1⁰ (south-west)

Explanation:

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3 years ago

A 62-kg person jumps from a window to a fire net 20.0 m directly below, which stretches the net 1.4 m. Assume that the net behav

gayaneshka [121]

Answer:

a) x = 0.098

b) x = 2.72 m

Explanation:

(a) To find the stretch of the fire net when the same person is lying in it, you can assume that the net is like a spring with constant spring k. It is necessary to find k.

When the person is falling down he acquires a kinetic energy K, this energy is equal to the elastic potential energy of the net when it is max stretched.

Then, you have:

$K=U\\\\\frac{1}{2}mv^2=\frac{1}{2}kx^2$ (1)