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AleksAgata [21]
3 years ago
12

If you mass 35kg on earth what will your mass be on the moon where gravity is 1/6 that of earths. PLZZZZ HElP NEED ASAP

Physics
1 answer:
abruzzese [7]3 years ago
4 0

Answer:

Mass will be same on moon as on Earth but weight will be one-sixth of Earth.

Explanation:

Mass of a body doesn't depend on gravity. Mass is a constant quantity. So, mass on moon will be same as mass on Earth.

But, the weight of a body depends on gravity as weight is given as:

\textrm{Weight}=\textrm{mass}\times \textrm{acceleration due to gravity}

Therefore, if g is acceleration due to gravity on Earth, then weight on Earth is, W_{E}=mg

Now, gravity on moon is one-sixth of Earth. So, g_{moon}=\frac{1}{6}g

Therefore, weight of the body on moon is, W_{moon}=mg_{moon}=m\times \frac{1}{6}g=\frac{1}{6}mg=\frac{1}{6}W_{E}

Therefore, a body has same mass both on moon and Earth but weight on moon is one-sixth of the weight on Earth.

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A spacecraft has a momentum of 20,000 kg-m/s, and a mass of 250 kg. What is the magnitude of its velocity?
Harlamova29_29 [7]

Answer:

<h2>A. 80 m/s </h2>

Explanation:

The velocity of the spacecraft can be found by using the formula

v =  \frac{p}{m}  \\

p is the momentum

m is the mass

From the question we have

v =  \frac{20000}{250}  =  \frac{2000}{25}  \\

We have the final answer as

<h3>80 m/s</h3>

Hope this helps you

6 0
3 years ago
What is the speed of a car that travels 0.200 km in 95 seconds? State your answer in meters per second.
WARRIOR [948]

Answer:

<h2>2.10 meters per second</h2><h2 />

Explanation:

speed (velocity) = distance / time

                          = <u>0.2 km (1000 m/km) </u>

                                     95 secs.

                          = 2.10 meters per second

8 0
3 years ago
4.A 200 kg cannon fires a 5 kg chicken into the air at a velocity of 100
exis [7]

Answer:

-2.5

Explanation:

5kg in grams = 5000

200kg in grams = 200,000

V2 = - (M1/M2) V1

Vc = - (Mh/Mc) Vh

Vc = - (5000/200000) 100

Vc = -2.5 units/second

4 0
2 years ago
What is the apparent weight of this same object at Neptune's equator? (Note that Neptune's "surface" is gaseous, not solid, so i
guajiro [1.7K]

Answer:

Explanation:

Acceleration of gravity on the surface of

Neptune is given

g' = G M/R^2,

where M is the planet's mass.

M g' will be the apparent weight registed at the poles.

G is the universal constant of gravity

The "apparent weight" at the equator will be

reduced from M g' by the centripetal force M

R w^2, where w is the rotational angular

velocity in radians/s), which you can deduce

from the 16 hour length of a day.

5 0
3 years ago
Read 2 more answers
1. This image shows the various forces acting on a block of rock situated on a rock slope. What does arrow 4 represent?
Gelneren [198K]

Answer:

B. Gravitational force

Explanation:

The gravitational force of an object (also called weight) is given by

F=mg

where m is the mass of the object and g is the acceleration of gravity, and it always points in the downward direction.

In this problem, the arrow labelled with 4 is the only force pointing downward: therefore, it must be the gravitational force.

The other arrows represent:

1 --> component of the gravitational force parallel to the plane

2 --> force of friction

3 --> component of the gravitational force perpendicular to the plane

8 0
3 years ago
Read 2 more answers
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