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BlackZzzverrR [31]
1 year ago
15

What energy is required to remove the remaining electron from singly ionized helium?

Chemistry
1 answer:
skelet666 [1.2K]1 year ago
3 0

To remove one electron from singly ionized helium, will require approximately 54.4 eV or 8.72 1020 J of energy.

The amount of energy required by an isolated, gaseous molecule in the electronic state of the ground to absorb in order to discharge an electron and produce a cation has been known as the ionization energy. The amount of energy required for every atom in a mole to drop one electron is most often given as kJ/mol.

Anything that causes electrically neutral atoms and molecules to gain or lose electrons in order to become electrically charged atoms as well as molecules .

Therefore, the "To remove one electron from singly ionized helium, will require approximately 54.4 eV or 8.72 1020 J of energy."

To know more about electron

brainly.com/question/14135172

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What is the valency of aluminium and nitrate in Al (NO3)3​
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Answer:

Aluminum loses three valence shell electrons to become the aluminum ion Al+3. Nitrate is a polyatomic ion with the formula NO3 -1.

6 0
3 years ago
What is the molarity of a solution containing 9.0 moles of solute in 2500 ml of a solution​
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M=(mols/L) so M=(9.0/2.5) which is 3.6M
7 0
3 years ago
What is the overall enthalpy of reaction for the equation shown below?
Rudiy27

Answer:

ΔH₁₂ = -867.2 Kj

Explanation:

Find enthalpy for 3H₂ + O₃ => 3H₂O given ...

2H₂ + O₂ => 2H₂O      ΔH₁ = -483.6 Kj

        3O₂ => 2O₃        ΔH₂ = + 284.6 Kj

_____________________________

3(2H₂ + O₂ => 2H₂O) => 6H₂ + 3O₂ => 6H₂O       (multiply by 3 to cancel O₂)

6H₂ + 3O₂ => 6H₂O        ΔH₁ = 3(-483.6 Kj) = -1450.6Kj

          2O₃ => 3O₂           ΔH₂ = -284.6Kj              (reverse rxn to cancel O₂)

_______________________________

6H₂ + 2O₃ => 6H₂O         ΔH₁₂ = -1735.2 Kj       (Net Reaction - not reduced)

________________________________

divide by 2 => target equation (Net Reaction - reduced)

3H₂ + O₃ => 3H₂O            ΔH₁₂ = (-1735.2/2) Kj = -867.2 Kj    

4 0
3 years ago
PLEASE HELP <br> What is the pH of a weak acid solution that has an [H+] of 2.1 × 10^–6 M
sveticcg [70]

Answer:

pH ( potential Hydrogen ) is a negative logarithm of molar concentration of hydrogen ions.

pH =  -  log[H {}^{ + } ]

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Answer:

C2= 0.16M

Explanation:

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Applying dilution formula

C1V1= C2V2

2×20 =C2×250

C2= 0.16M

5 0
3 years ago
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