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BlackZzzverrR [31]
1 year ago
15

What energy is required to remove the remaining electron from singly ionized helium?

Chemistry
1 answer:
skelet666 [1.2K]1 year ago
3 0

To remove one electron from singly ionized helium, will require approximately 54.4 eV or 8.72 1020 J of energy.

The amount of energy required by an isolated, gaseous molecule in the electronic state of the ground to absorb in order to discharge an electron and produce a cation has been known as the ionization energy. The amount of energy required for every atom in a mole to drop one electron is most often given as kJ/mol.

Anything that causes electrically neutral atoms and molecules to gain or lose electrons in order to become electrically charged atoms as well as molecules .

Therefore, the "To remove one electron from singly ionized helium, will require approximately 54.4 eV or 8.72 1020 J of energy."

To know more about electron

brainly.com/question/14135172

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Novay_Z [31]
Data: 
M_{concentrated} = 2.5\:mol
V_{concentrated} = ?
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V_{dilute} = 100\:mL\to0.100\:L
<span>
Formula: Dilution Calculations

</span>M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
<span>
Solving:

</span>
M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
2.5 * V_{concentrated} = 0.50 * 0.100
2.5V_{concentrated} = 0.05
V_{concentrated} =  \frac{0.05}{2.5}
\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark<span>







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