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Elina [12.6K]
2 years ago
15

Assessment

Chemistry
1 answer:
MakcuM [25]2 years ago
4 0

i didn’t mean to put this opps

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A sample of 1.00 moles of oxygen at 50°C and 98.6 kPa, occupies what volume?
enyata [817]

Answer:

27.22 dm³

Explanation:

Given parameters:

number of moles = 1 mole

temperature= 50°C, in K gives 50+ 273 = 323K

Pressure= 98.6kpa in ATM, gives 0.973 ATM

Solution:

Since the unknown is the volume of gas, applying the ideal gas law will be appropriate in solving this problem.

The ideal gas law is mathematically expressed as,

Pv=nRT

where P is the pressure of the gas

V is the volume

n is the number of moles

R is the gas constant

T is the temperature

Input the parameters and solve for V,

0.973 x V = 1 x 0.082 x 323

V= 27.22 dm³

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3 years ago
Given the following chemical reaction: 2 O2 + CH4 --> CO2 + 2 H2O
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The answer is D) 144 grams O2
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The following two compounds each exhibit two heteroatoms (one nitrogen atom and one oxygen atom). In compound A, the lone pair o
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Answer:

The answer is the photo attached

Explanation:

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2 years ago
Which is a possible result of rising ocean temperatures caused by global warming?
goldfiish [28.3K]
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3 years ago
The volume of 1.20 lol of gas at 61.3 kPa and 25.0 degree Celsius is
aniked [119]

Answer:

V = 48.5 L

Explanation:

Converting °C to K and kPa to atm

T = 25.0°C + 273.15 = 298.15 K

P = 61.3 kPa × (1 atm / 101.325 kPa) = 0.60498 atm

Calculating the volume of gas

V = nRT / P

V = (1.20 mol)(0.082057 L•atm/mol•K)(298.15 K) / 0.60498 atm

V = 48.5 L

4 0
2 years ago
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