While waves that travel within the depths of the ocean are longitudinal waves
Explanation : the waves that travel along the surface of the oceans are referred to as surface waves. A surface wave is a wave in which particles of the medium undergo a circular motion. Surface waves are neither longitudinal nor transverse.
Answer:
Explanation:
carbon in group 4A needs 4 more electrons to be stable
hydrogen in group 1A has one electron needs 1 more t o be stale
oxygen in group 6A has 6 and needs 2 more to be stable
They all obtain this by sharing electrons 8 around C &O, 2 around H
H : C: H
::
:O:
The number of molecules= 3.55 x 10²⁴
<h3>Further explanation</h3>
Given
5.9 moles of NaCl
Required
The number of molecules
Solution
The mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
So for 5.9 moles :
= 5.9 x 6.02 x 10²³
= 3.55 x 10²⁴
Answer:
![Kc=\frac{[CH_{3}OH]}{[CO].[H_{2}]^{2} }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BCH_%7B3%7DOH%5D%7D%7B%5BCO%5D.%5BH_%7B2%7D%5D%5E%7B2%7D%20%7D)
Explanation:
Let's consider the following reaction.
CO(g) + 2 H₂(g) ⇌ CH₃OH(g)
The equilibrium constant (Kc) is <em>the products of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients.</em>
![Kc=\frac{[CH_{3}OH]}{[CO].[H_{2}]^{2} }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BCH_%7B3%7DOH%5D%7D%7B%5BCO%5D.%5BH_%7B2%7D%5D%5E%7B2%7D%20%7D)
If you wanted to calculate [CH₃OH], suppose that the molar concentrations for CO and H₂ at equilibrium are [CO] = 0.04 M and [H₂] = 0.08 M. The concentration of methanol at equilibrium is:
![Kc= 2.3 \times 10^{4} = \frac{[CH_{3}OH]}{[CO].[H_{2}]^{2} } =\frac{[CH_{3}OH]}{(0.04).(0.08)^{2} }\\ \ [CH_{3}OH]=5.9M](https://tex.z-dn.net/?f=Kc%3D%202.3%20%5Ctimes%2010%5E%7B4%7D%20%3D%20%5Cfrac%7B%5BCH_%7B3%7DOH%5D%7D%7B%5BCO%5D.%5BH_%7B2%7D%5D%5E%7B2%7D%20%7D%20%3D%5Cfrac%7B%5BCH_%7B3%7DOH%5D%7D%7B%280.04%29.%280.08%29%5E%7B2%7D%20%7D%5C%5C%20%5C%20%5BCH_%7B3%7DOH%5D%3D5.9M)
Kinetic energy. I’m pretty sure that that that that is is so the right answe