Answer:
The final balanced equation is :

Explanation:

Balancing in acidic medium:
First we will determine the oxidation and reduction reaction from the givne reaction :
Oxidation:

Balance the charge by adding 2 electrons on product side:
....[1]
Reduction :

Balance O by adding water on required side:

Now, balance H by adding
on the required side:

At last balance the charge by adding electrons on the side where positive charge is more:
..[2]
Adding [1] and [2]:

The final balanced equation is :

Answer:
Explanation:
1) A fulcrum is a pivot point that plays a central role (not necessarily located at the center) in a lever. The fulcrum of the attached picture has been circled (in blue).
2) The object placed on this lever's measurement tray is balanced by placing it at the center of the tray. This is the standard way of placing objects on any balance.
Answer:
Igneous rock is the type of rock that forms as a result of cooling an crystallization
Explanation:
- Rocks are either sedimentary, igneous or metamorphic based on the chemical composition and the mode of formation.
- Igneous rocks are formed as a result of the cooling and crystallization of magma from volcanic eruptions.
- Igneous rocks are either intrusive, which form deep in the crust or extrusive which form on the surface of the earth.
- Sedimentary rocks are formed as a result of deposition, and cementation of sediments.
- Metamorphic rocks, on the other hand, are formed from the sedimentary and igneous rocks during the rock cycle.
A straight chain hydrocarbon with the formula C5 H10: has a double C-C bond
Hello!
The correct answer is 1. KCI.
I really hope this helped you out! c: