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Viktor [21]
3 years ago
15

When a mass increases, its gravitational force_____.

Physics
1 answer:
Reil [10]3 years ago
8 0
The correct answer is A
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Intuitively, which of the following would happen to E⃗ net if d became very large? E⃗ net should reduce to the field of a point
mart [117]

Answer:

A C

Explanation:

The statement of the exercise is a bit strange, but if the distance between the load increases.

The following phenomena must occur.

* If the charge has a spatial distribution, the electric field should reduce the electric field of a point charge at the same distance

* As the distance increases the value of the electric field decreases in quadratic form

therefore when reviewing the correct answers are

if the total load is q, answer A is correct

and answer C is always correc

5 0
4 years ago
A small pebble and one large boulder start at the same height and begin rolling down the side of a mountain. Which object would
vitfil [10]

Answer:

The small pebble

Explanation:

Since the potential energy, P.E lost equals kinetic energy, K.E gained,

P.E = K.E

P.E = mgh = K.E

So, K.E = mgh where g = acceleration due to gravity and h = height of drop

Since h and g are constant

K.E ∝ m

So, the kinetic energy of the object is directly proportional to its mass. Thus, the object with the smaller mass has the lesser kinetic energy.

Since the object with the smaller mass is the small pebble, so the small pebble would have less kinetic energy as it crashes on the road at the bottom of the mountain.

8 0
3 years ago
A vinyl record is played by rotating the record so that an approximately circular groove in the vinyl slides under a stylus. Bum
Fed [463]

Answer:

983.400345675 hits per second

Explanation:

Radius = 14.2 cm

Record turn rate = 33 rev/min

Bump separation = 0.499 mm

Circumference of the record = 2\pi 0.142=0.89221231362\ m

Number of bumps in the groove = \dfrac{0.89221231362}{0.499\times 10^{-3}}=1788.0006285\ bumps

The rate which the bumps hit the stylus = 33\times\dfrac{1788.0006285}{60}=983.400345675

The rate at which the bumps hit the stylus 983.400345675 hits per second

8 0
3 years ago
Light shines through a single slit whose width is 5.7 x 10-4 m. A diffraction pattern is formed on a flat screen located 4.0 m a
lilavasa [31]

Answer:

\lambda = 570\ nm

Explanation:

Given,

Width of slit, W = 5.7 x 10⁻⁴ m

Distance between central bright fringe, L = 4 m

distance between central bright fringe and first dark fringe, y = 4 mm

Diffraction angle

tan \theta = \dfrac{y}{L}

tan \theta = \dfrac{4}{4\times 10^3}

\theta = 0.0572

Now.

W sin \theta = m \lambda

m = 1

5.7 \times 10^{-4} \times sin (0.0572) = 1 \times \lambda

\lambda = 569.99 \times 10^{-9}\ m

\lambda = 570\ nm

4 0
4 years ago
Find the mass of a 4 N stone.
nikitadnepr [17]

Answer:

F=ma

4=m(9.8)

m=2.45kg

6 0
3 years ago
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