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lakkis [162]
3 years ago
10

Find the mass of a 4 N stone.

Physics
1 answer:
nikitadnepr [17]3 years ago
6 0

Answer:

F=ma

4=m(9.8)

m=2.45kg

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If a soundproof door is almost shut but still leaves a small opening, what wave phenomenon is responsible for someone being able
lana66690 [7]

The phenomenon which is responsible for this effect is called diffraction.

Diffraction is the ability of a wave to propagate when it meets an obstacle or a slit. When the wave encounters the obstacle or the slit, it 'bends' around it and it continues propagate beyond it. A classical example of this phenomenon is when a sound wave propagates through a wall where there is a small aperture (as in the example of this problem)

5 0
4 years ago
Read 2 more answers
2. A 3.0 kg block rests on a level surface. The coefficient of static friction is µs = 0.50, and the coefficient of kinetic fric
yan [13]
Friction force is equal to the applied force F until the block starts moving. Hence, it will increase until the maximum value of 3.0*10*0.50=150 N. 

While it's moving, the friction will be 3.0*10*0.2 = 60 N, constant. The rest of the applied force will accelerate the block.

6 0
3 years ago
Choose the 200 kg refrigerator. set the applied force to 400 n (to the right). be sure friction is turned off. what is the net f
Firlakuza [10]

The net force acting on the refrigerator is 400 N to the right.

<h3></h3><h3>FURTHER EXPLANATION</h3>

The net force or resultant force is the sum of all the forces acting on a body or an object in x and y axes.

  • Forces along the y-axis The forces that usually act on an object vertically (in the y-axis) are: gravitational force which is a downward force and the normal force which is an upward (perpendicular) force exerted by a surface on an object resting above it that keeps the object from falling.
  • Forces along the x-axis These include the force or forces applied to cause a left or right motion of an object along the horizontal plane (called the Applied Force) and the force that opposes the motion or friction.

In this problem the forces acting on the x and y - axes can be determined:

Along the x-axis:

  • gravitational force = -1960 N
  • normal force = +1960 N
  • Net force = -1960 N + 1960 N = 0

The gravitational force is the weight of the object obtained by multiplying the mass of the object (in kg) with the acceleration due to gravity, 9.8 m/s^2. It is given a negative (-) sign to indicate that it is a downward force.

Since the object is not falling through the surface, it can be assumed that the gravitational force and normal force are balanced. Hence, the size of the normal force is the same as the gravitational force but with the opposite direction indicated by the + sign for an upward force.

The forces along the x-axis are balanced  (i.e. net force is zero) so the object neither moves upward or downward.

Along the y-axis

  • applied force = +400 N
  • friction = 0
  • Net force = +400 N + 0 = +400 N

The applied force is +400 N. It is given a + sign to indicate that its direction is to the right.

The friction, as mentioned in the problem, is set to zero or "turned off".

The net force along the y-axis is +400. The forces are unbalanced so the object will move to the right as force is applied to it.

<h3>LEARN MORE</h3>
  • Balanced Forces brainly.com/question/760473
  • Unbalanced Forces brainly.com/question/4289010
  • Free body Diagrams brainly.com/question/12345810

Keywords: net force, resultant force

5 0
4 years ago
Read 2 more answers
Eye at the lowest radiated power of 1,2 x10 x (- 17) W. Determine how many photons of light with a wavelength of 500nm fall on t
mars1129 [50]

Answer:

\frac{n}{t} = 30\ photons/s

Explanation:

The radiated power can be given in terms of the wavelength as follows:

Rasiated\ Power = \frac{nE}{t} = \frac{nhc}{\lambda t}

where,

Radiated Power = 1.2 x 10⁻¹⁷ W

n = no. of photons = ?

h = plank's constant = 6.625 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength = 500 nm = 5 x 10⁻⁷ m

t = time

Therefore,

1.2\ x\ 10^{-17}\ W = \frac{n(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{(5\ x\ 10^{-7}\ m)(t) }\\\\\frac{n}{t} = \frac{1.2\ x\ 10^{-17}\ W}{3.975\ x\ 10^{-19}\ J}\\\\\frac{n}{t} = 30\ photons/s

8 0
3 years ago
2.3mol of monatomic gas A initially has 4700J of thermal energy. It interacts with 2.6mol of monatomic gas B, which initially ha
rewona [7]

Answer:

Gas B has the higher initial temperature

6,199 J

7,008 J

Explanation:

Mathematically;

The thermal energy of a gas is given by:

E = 3/2 n kT

Where n is the number of moles, K is the molar gas constant and T is the temperature

For Gas A;

4700 = 1.5 * 2.3 * 8.31 * T

T = 4700/28.6695

Thus, T = 163.94 K

For gas B

8500 = 1.5 * 2.6 * 8.31 * T

T = 8500/32.409

T = 262.27 K

This means that gas B has a higher temperature than gas A.

At equilibrium, temperature

T = naTa + nbTb / (na + nb )

T = [2.3(163.94) + 2.6(262.27)]/(2.3 + 2.6)

T = [377.062 + 681.902]/4.9 = 216.12 K

216.12 K is the equilibrium temperature

= 216.12 K is the equilibrium temperature.

Thus, final thermal energy of Gas A and B

Gas A = 1.5 * 2.3 * 8.314 * 216.12= 6,199 J

Gas B = 1.5 * 2.6 * 8.314 * 216.12 = 7,008 J

5 0
4 years ago
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