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Katen [24]
4 years ago
14

Intuitively, which of the following would happen to E⃗ net if d became very large? E⃗ net should reduce to the field of a point

charge of magnitude q. E⃗ net should reduce to the field of a point charge of magnitude 4q. The larger d becomes, the smaller the magnitude of E⃗ net will be. The larger d becomes, the greater the magnitude of E⃗ net will be. Enter the letters of all the correct answers in alphabetical order. Do not use commas. For instance, if you think that A and D are correct, enter AD.
Physics
1 answer:
mart [117]4 years ago
5 0

Answer:

A C

Explanation:

The statement of the exercise is a bit strange, but if the distance between the load increases.

The following phenomena must occur.

* If the charge has a spatial distribution, the electric field should reduce the electric field of a point charge at the same distance

* As the distance increases the value of the electric field decreases in quadratic form

therefore when reviewing the correct answers are

if the total load is q, answer A is correct

and answer C is always correc

You might be interested in
In the photoelectric effect, a photon with an energy of 5.3 × 10–19 J strikes an electron in a metal. Of this energy, 3.6 × 10–1
valentina_108 [34]

Answer:

The velocity of the photo electron is 6.11\times 10^5\ m/s.

Explanation:

Given that,

Supplied energy, E_s=5.3\times 10^{-19}\ J

Minimum energy of the electron to escape from the metal, E_e=3.6\times 10^{-19}\ J

We need to find the velocity of the photo electron. The energy supplied by the photon is equal to the sum of minimum escape energy and the kinetic energy of the escaping electron. So,

5.3\times 10^{-19}\ J=3.6\times 10^{-19}\ J+K\\\\K=5.3\times 10^{-19}-3.6\times 10^{-19}\\\\K=1.7\times 10^{-19}\ J

The formula of kinetic energy is given by :

K=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{2K}{m}} \\\\v=\sqrt{\dfrac{2\times 1.7\times 10^{-19}}{9.1\times 10^{-31}}} \\\\v=6.11\times 10^5\ m/s

So, the velocity of the photo electron is 6.11\times 10^5\ m/s.

4 0
3 years ago
Lasers are now used in eye surgery. Given the wavelength of a certain laser is 514 nm and the power of the laser is 1.1 W, how m
Leno4ka [110]

Answer: 1.593*10^{17} photons released if the laser is used 0.056 s during the surgery

                           

Explanation:

First, you have to calculate the energy of each photon according to Einstein's theoty, given by:

                            E =\frac{hc}{\lambda}

Where \lambda is the wavelength, h is the Planck's constant and  h is the speed of light

              h = 6.626*10^{-34} \frac{m^{2} kg }{s}  -> Planck's constant

              c = 3*10^{8} \frac{m}{s}  -> Speed of light

So, replacing in the equation:

                E =\frac{ 6.626*10^{-34} \frac{m^{2} kg }{s}*3*10^{8} \frac{m}{s}}{514*10^-9 m}

Then, the energy of each released photon by the laser is:

                E = 3.867*10^{-19} \frac{J}{photons}

After, you do the inverse of the energy per phothon and as a result, you will have the number of photons in a Joule of energy:

               \frac{1}{3.867*10^{-19}} = 2.586*10^{18} \frac{photons}{J}

The power of the laser is 1.1 W, or 1.1 J/s, that means that you can calculate how many photons the laser realease every second:

              2.586*10^{18}\frac{photons}{J} * 1.1 \frac{J}{s} = 2.844*10^{18} \frac{photons}{s}

And by doing a simple rule of three, if 2.844*10^{18} photons are released every second, then in 0.056 s:

            0.056 s*2.844*10^{18} \frac{photons}{s} = 1.593*10^{17} photons are released during the surgery

5 0
3 years ago
The question is on the picture.
Jet001 [13]
Between noon and 2 pm, the amount of water in the rain gauge decreased.
This can be caused by evaporation, which turns water into water vapor.
Precipitation would increase the amount of rain water in the gauges, not decrease it.
Condensation occurs after evaporation but wouldn't decrease the water in the gauges by itself.
Runoff is when water on land drains into water sources such as lakes, rivers, oceans, etc. 
So the answer is A. evaporation.
5 0
3 years ago
Read 2 more answers
Rob is studying for an exam. He listed some properties of magnets in a Maglev train.
fredd [130]
The answer is the third one. Maglev is short for Magnetic Levitation in which trains skim on a guideway utilizing the guideline of attractive shock. Every magnet has two shafts. Presently in the event that you play with two magnets, you'll understand that inverse shafts pull in, though comparable posts repulse. This shocking property of magnets is utilized as a part of Maglev trains. However,instead of utilizing lasting magnets, the standard of electromagnetism is utilized to make solid and huge impermanent magnets. At the point when an electric current is gone through a loop of wire, attractive field is created around the curl as indicated by Faraday's laws.
7 0
3 years ago
Read 2 more answers
Given a force of 100 N and an acceleration of 10 m/s^2, what is the mass?
frutty [35]

Given:

Force(F): 100 N

Acceleration: 10 m/s^2

Now we know that

F= mx a

Where F is the force acting on the object which is measured in Newton

m is the mass of the object measured in Kg

a is the acceleration measured in m/s^2

Substituting the given values in the above formula we get

100= 10m

m= 10 Kg

6 0
3 years ago
Read 2 more answers
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