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Katen [24]
4 years ago
14

Intuitively, which of the following would happen to E⃗ net if d became very large? E⃗ net should reduce to the field of a point

charge of magnitude q. E⃗ net should reduce to the field of a point charge of magnitude 4q. The larger d becomes, the smaller the magnitude of E⃗ net will be. The larger d becomes, the greater the magnitude of E⃗ net will be. Enter the letters of all the correct answers in alphabetical order. Do not use commas. For instance, if you think that A and D are correct, enter AD.
Physics
1 answer:
mart [117]4 years ago
5 0

Answer:

A C

Explanation:

The statement of the exercise is a bit strange, but if the distance between the load increases.

The following phenomena must occur.

* If the charge has a spatial distribution, the electric field should reduce the electric field of a point charge at the same distance

* As the distance increases the value of the electric field decreases in quadratic form

therefore when reviewing the correct answers are

if the total load is q, answer A is correct

and answer C is always correc

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The gravity of Neptune is about 1.1 times the gravity of earth. How will the mass of an object on Neptune compare with its mass
Roman55 [17]
I think the gravity doesn't affect the mass of an object. Only it's weight can be compared
7 0
3 years ago
Read 2 more answers
At t = 0, one toy car is set rolling on a straight track with initial position 13.0 cm, initial velocity -3.6 cm/s, and constant
Klio2033 [76]

Answer:

that's too much to read

8 0
3 years ago
Sam receives the kicked football on the 3 yd line and runs straight ahead toward the goal line before cutting to the right at th
Pie

Answer:

Distance: 21 yd, displacement: 15 yd, gain in the play: 12 yd

Explanation:

The distance travelled by Sam is just the sum of the length of each part of Sam's motion, regardless of the direction. Initially, Sam run from the 3 yd line to the 15 yd line, so (15-3)=12 yd. Then, he run also 9 yd to the right. Therefore, the total distance is

d = 12 + 9 = 21 yd

The displacement instead is a vector connecting the starting point with the final point of the motion. Sam run first 12 yd straight ahead and then 9 yd to the right; these two motions are perpendicular to each other, so we can find the displacement simply by using Pythagorean's theorem:

d=\sqrt{12^2+9^2}=15 yd

Finally, the yards gained by Sam in the play are simply given by the distance covered along the forward-backward direction only. Since Sam only run from the 3 yd line to the 15 yd line along this direction, then the gain in this play was

d = 15 - 3 = 12 yd

7 0
3 years ago
g stAn experienced spear fisherman sees a small fish swimming in a tidal pool. If the fisherman sees the fish at approximately a
Luba_88 [7]

Answer:

  θ = 28.9

Explanation:

For this exercise let's use the law of refraction

          n₁ sin θ₁ = n₂ sin θ₂

where we use index 1 for air and index 2 for water where the fish is

        sin θ₂ = n₁ / n₂ sin θ₁

in this case the air repair index is 1 and the water 1.33

we substitute

        sin θ₂ = 1 / 1.33 sin t 40

        sin θ = 0.4833

         

        θ = sin⁻¹ 0.4833

        θ = 28.9

5 0
3 years ago
Consider five atoms from the second period : lithium , beryllium , boron , carbon , and nitrogen , which of these elements has t
kap26 [50]

Answer:

Lithium has the lowest electronegativity.

Explanation:

Electronegativity measures the tendency of an atom to attract the bonding pair of electrons. As we move left to right in a period, the number of shell remains same but the number of electron increases(negative charge increases. Hence, electronegativity also increases.

As Lithium is the left most element in this period. It has the lowest electronegativity value which is equal to 0.98.

6 0
3 years ago
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