Question

Paola can flex her legs from a bent position through a distance of 20.1 cm. Paola leaves the ground when her legs are straight,

Answer 1

The third equation of free fall can be applied to determine the acceleration. So that Paola's acceleration during the flight is 39.80 m/$s^{2}$.

Acceleration is a quantity that has a direct relationship with velocity and also inversely proportional to the time taken. It is a vector quantity.

To determine Paola's acceleration, the third equation of free fall is appropriate.

i.e $V^{2}$ = $U^{2}$ ± 2as

where: V is the final velocity, U is the initial velocity, a is the acceleration, and s is the distance covered.

From the given question, s = 20.1 cm (0.201 m), U = 4.0 m/s, V = 0.

So that since Poala flies against gravity, then we have:

$V^{2}$ = $U^{2}$ - 2as

0 = $(4)^{2}$ - 2(a x 0.201)

  = 16 - 0.402a

0.402a = 16

a = $\frac{16}{0.402}$

  = 39.801

a = 39.80 m/$s^{2}$

Therefore Paola's acceleration is 39.80 m/$s^{2}$.

Visit: brainly.com/question/17493533

Answer 2

Answer:

Magnitude of Paula’s acceleration$a=39 \cdot 8m/sec^{2} .$

Explanation:

• An object is said to be accelerated if there is a change in its velocity. At any point on a trajectory, the magnitude of the acceleration is given by the rate of change of velocity in both magnitude and direction at that point.

• To find the magnitude of her acceleration, use the formula:                               ${v^2} = {u^2} + 2as$

Where, is final velocity, is initial velocity, is acceleration and is displacement.

• Placing the value of the given initial velocity, $u=0m/s$, displacement, $s = 0 \cdot 201m$ and the final velocity,$v = 4m/s$ in the above formula.

$\[\begin{align}& \therefore{v^2} = {u^2} + 2as \\& \Rightarrow {\left( 4 \right)^2} = 0+ 2\left( a \right) \left( { 0 \cdot 201} \right) \\& \Rightarrow 16 = 0 \cdot 402a \\& \Rightarrow a = 39 \cdot 8m/sec^{2} \\\end{align}\]$

$\[& \therefore{v^2} = {u^2} + 2as \\& \Rightarrow {\left( 4 \right)^2} = 0+ 2\left( a \right) \left( { 0 \cdot 201} \right) \\& \Rightarrow 16 = 0 \cdot 402a \\& \Rightarrow a = 39 \cdot 8m/sec^{2} \\\]$

• Hence, magnitude of her acceleration, $a=39 \cdot 8m/sec^2$

Learn more about acceleration here:

https://brainly.in/question/46561476?tbs_match=1