Answer:
ΔT = 1.22*10^-3 °C
Explanation:
First, you calculate the potential energy of the bird when it is at 35 m high. The potential energy is also the mechanical energy of the bird in this case.
m: mass of the bird = 0.75kg
g: gravitational constant = 9.8m/s^2
h: height = 35m
All this energy is given to the water. You use the following formula in order to calculate the change in temperature:
m: mass of the water = 50kg
c: specific heat of water = 4186 J/kg°C
Q is equal to U (potential energy of the bird) because the bird gives all its energy to water. By doing ΔT the subject of the formula you obtain:
hence, the maximum rise in temperature is 0.00122 °C
REALISM shows things as they REALLY look.
Answer:
<em>Percentage error = 2.63%</em>
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Explanation:
We are given the following
Original volume = 15.20mL
Student measurement = 14.8mL
Error = 15.20-14.80
Error = 0.40mL
percentage = Error/Original volume * 100
Percentage error = 0.4/15.20 * 100
Percentage error = 40/15.20
<em>Percentage error = 2.63%</em>
<em></em>
Answer:
421.83 m.
Explanation:
The following data were obtained from the question:
Height (h) = 396.9 m
Initial velocity (u) = 46.87 m/s
Horizontal distance (s) =...?
First, we shall determine the time taken for the ball to get to the ground.
This can be calculated by doing the following:
t = √(2h/g)
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) = 396.9 m
Time (t) =.?
t = √(2h/g)
t = √(2 x 396.9 / 9.8)
t = √81
t = 9 secs.
Therefore, it took 9 secs fir the ball to get to the ground.
Finally, we shall determine the horizontal distance travelled by the ball as illustrated below:
Time (t) = 9 secs.
Initial velocity (u) = 46.87 m/s
Horizontal distance (s) =...?
s = ut
s = 46.87 x 9
s = 421.83 m
Therefore, the horizontal distance travelled by the ball is 421.83 m
Explanation:
define the term specific heat capacity of water
