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KonstantinChe [14]
3 years ago
7

Which one of the following items does NOT characterize a reducing agent? a. A reducing agent loses electrons. b. A reducing agen

t causes another species to be reduced. c. The oxidation number of a reducing agent increases. d. A good reducing agent is a metal in a high oxidation state, such as Mn7+.
Chemistry
1 answer:
Ad libitum [116K]3 years ago
4 0

Answer: D

Explanation:

A reducing agent is a species that reduces other compounds, and is thereby oxidized. The whole compound becomes the reducing agent. In other words, of a compound is oxidized, then they are the reducing agent. On the other hand, if the compound is reduced, it is an ozidizing agent.

Since we have established that a reducing agent is the compound being oxidized, we know that A is not our answer. An oxidized compound is losing electrons. Choice A states exactly this.

For B, this is true as we have established this already.

C is also correct. Since a reducing agent loses electrons, it becomes more positive. This makes the oxidation number increase.

D would be our correct answer. It is actually a good oxidizing agent is a metal in a high oxidation state, such as Mn⁷⁺.

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A 0.2 M carboxylic acid (RCOOH) has a Ka = 1.66x10-6. What is the pH of this solution? Enter to 2 decimal places.
maria [59]

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3.24

Explanation:

The dissociation equation for the carboxylic acid can be represented as follows:

RCOOH —-> RCOO- + H+

We can use an ICE table to get the value of the concentration of the hydrogen ion. ICE stands for initial, change and equilibrium.

RCOOH RCOO- H+

Initial 0.2 0.0. 0.0

Change -x +x. +x

Equilibrium 0.2-x. x. x

We can now find the value of x as follows:

Ka = [RCOO-][H+]/[RCOOH]

(1.66* 10^-6) = (x * x)/(0.2-x)

(1.66 * 10^-6) (0.2-x) = x^2

x^2 = (3.32* 10^-7) - (1.66*10^-6)x

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Solving the quadratic equation to get x:

x = 0.0005753650094369094 or - 0.0005753650094369094

As concentration cannot be negative, we discard the negative answer

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pH = -log(0.0005753650094369094)

pH = 3.24

8 0
3 years ago
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