Answer:
g
Step-by-step explanation:
9514 1404 393
Answer:
- square: 12 ft sides
- octagon: 6 ft sides
Step-by-step explanation:
This problem can be worked in your head.
If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.
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We can let s represent the side length of the octagon. Then we have ...
8s = perimeter of octagon
4(s +6) = perimeter of square
These are equal, so ...
4(s +6) = 8s
s +6 = 2s . . . . . . divide by 4
6 = s . . . . . . . . . . subtract s
The octagon has 6-ft sides; the square has 12-ft sides.
The probability would be 0.1971.
We will calculate a z-score for each end of this interval.
z = (X-μ)/σ
For the lower limit:
z = (1100-1050)/218 = 50/218 = 0.23
For the upper limit:
z = (1225-1050)/218 = 175/218 = 0.80
Using a z-table (http://www.z-table.com) we see that the area under the curve to the left of, less than, the lower limit is 0.5910. The area under the curve to the left of, less than, the upper limit is 0.7881. To find the area between them, we subtract:
0.7881 - 0.5910 = 0.1971
Answer:
linear
Step-by-step explanation:
Mistake in Line 2 : Was in the determining the values for a ,b,c
Mistake in Line 4 : Not taking the square roots of both sides.
Step-by-step explanation:
First Mistake : Line 2
Second Mistake : Line 4
Correct Solution :
