1) -12
ab is a times b. We plug in the numbers (-4)*(3) which equals -12.
2) 1
We plug in -4 for a, and 3 for b into the equation.
We get 2(-4) + 3(3)
2*-4 is -8. 3*3 is 9. We add them both, and -8+9 equals 1.
3) -14
We plug in -4 for a, and 3 for b into the equation.
2(-4-3)
-4-3 is -7. -7*2 equals -14.
Answer: 1st box- subtracting 8 from both sides
2nd box- -8
Step-by-step explanation:
Answer:
x = -2, x = 3 − i√8, and x = 3 + i√8
Step-by-step explanation:
g(x) = x³ − 4x² − x + 22
This is a cubic equation, so it must have either 1 or 3 real roots.
Using rational root theorem, we can check if any of those real roots are rational. Possible rational roots are ±1, ±2, ±11, and ±22.
g(-1) = 18
g(1) = 18
g(-2) = 0
g(2) = 12
g(-11) = 1782
g(11) = 858
g(-22) = -12540
g(22) = 8712
We know -2 is a root. The other two roots are irrational. To find them, we must find the other factor of g(x). We can do this using long division, or we can factor using grouping.
g(x) = x³ − 4x² − 12x + 11x + 22
g(x) = x (x² − 4x − 12) + 11 (x + 2)
g(x) = x (x − 6) (x + 2) + 11 (x + 2)
g(x) = (x (x − 6) + 11) (x + 2)
g(x) = (x² − 6x + 11) (x + 2)
x² − 6x + 11 = 0
Quadratic formula:
x = [ 6 ± √(36 − 4(1)(11)) ] / 2
x = (6 ± 2i√8) / 2
x = 3 ± i√8
The three roots are x = -2, x = 3 − i√8, and x = 3 + i√8.
Yay I guess I get points now. Lol
