Answer:
A&D
Step-by-step explanation:
i think
Find m∠BOC, if m∠MOP = 110°.
Answer:
m∠BOC= 40 degrees
Step-by-step explanation:
A diagram has been drawn and attached below.
- OM bisects AOB into angles x and x respectively
- ON bisects ∠BOC into angles y and y respectively
- OP bisects ∠COD into angles z and z respectively.
Since ∠AOD is a straight line
x+x+y+y+z+z=180 degrees

We are given that:
m∠MOP = 110°.
From the diagram
∠MOP=x+2y+z
Therefore:
x+2y+z=110°.
Solving simultaneously by subtraction

x+2y+z=110°.
We obtain:
x+z=70°
Since we are required to find ∠BOC
∠BOC=2y
Therefore from x+2y+z=110° (since x+z=70°)
70+2y=110
2y=110-70
2y=40
Therefore:
m∠BOC= 40 degrees
Answer:
10a: △ABC is an Equilateral triangle with all acute angles.
10b: △BCD is A scalene triangle with all acute angles.
10c: △BDE is An Isosceles triangle with one obtuse angle.
Step-by-step explanation:
10) Looking at the diagram at the bottom left;
- △ABC has 3 equal internal angles and as such, it means it will have 3 equal angles.
Thus, we can classify it as; Equilateral triangle with all acute angles.
- △BCD has 3 unequal angles. Thus, it's 3 sides are not equal. Also all the angles are less than 90°.
We can classify it as;
A scalene triangle with all acute angles
- △BDE has 2 equal angles and one angle greater than 90°. This means it has 2 equal sides.
Thus, we can classify it as;
- An Isosceles triangle with one obtuse angle.
1 crawdad/shrimp i believe
Answer:
x = 18.
Step-by-step explanation:
The 2 amgles are adjacent so add up to 180 degrees so we have:
x^2 - 11x + 3x = 180
x^2 - 8x - 180 = 0
(x -18)(x + 10) = 0
x = -10, 18.
x = -10 cannot be correct because that would make the 3x angle = -30.