Answer:
(I am not sure what the question means but according to what I understood I got these as my answers)
33 pounds = 55%
114 = 240 %
95% = 57 pounds
Answer: a) 0.6141
b) 0.9772
Step-by-step explanation:
Given : Mean : ![\mu= 62.3\text{ in}](https://tex.z-dn.net/?f=%5Cmu%3D%2062.3%5Ctext%7B%20in%7D)
Standard deviation : ![\sigma = \text{2.4 in}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Ctext%7B2.4%20in%7D)
The formula for z -score :
![z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
a) Sample size = 1
For x= 63 in. ,
![z=\dfrac{63-62.3}{\dfrac{2.4}{\sqrt{1}}}=0.29](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B63-62.3%7D%7B%5Cdfrac%7B2.4%7D%7B%5Csqrt%7B1%7D%7D%7D%3D0.29)
The p-value = ![P(z](https://tex.z-dn.net/?f=P%28z%3C0.29%29%3D)
![0.6140918\approx0.6141](https://tex.z-dn.net/?f=0.6140918%5Capprox0.6141)
Thus, the probability is approximately = 0.6141
b) Sample size = 47
For x= 63 ,
![z=\dfrac{63-62.3}{\dfrac{2.4}{\sqrt{47}}}\approx2.0](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B63-62.3%7D%7B%5Cdfrac%7B2.4%7D%7B%5Csqrt%7B47%7D%7D%7D%5Capprox2.0)
The p-value = ![P(z](https://tex.z-dn.net/?f=P%28z%3C2.0%29)
![=0.9772498\approx0.9772](https://tex.z-dn.net/?f=%3D0.9772498%5Capprox0.9772)
Thus , the probability that they have a mean height less than 63 in =0.9772.
Answer:
4 1/4 and from all the 1/2 bags they=2 lb
Answer:
24
Step-by-step explanation:
IDK