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liraira [26]
3 years ago
14

How do I graph standard form

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
5 0
Simple you just solve for y and put the equation in slope-intercept form
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Find the difference (7a-6b+7) - (8a-2)
olga nikolaevna [1]
Hey there!

Let's set up our expression:

(7a-6b+7)-(8a-2)

In order to simplify, we can use that subtraction sign and distribute it, using the distributive property. We have:

7a-6b+7-8a+2

Notice how it's plus two, because a negative times a negative two is a positive two. Now, it's a matter of finding the like terms and adding or subtracting them. These like terms can either have no variable, or have different coefficients but the same variable. That means our like terms are the 7a and -8a, and the 7 and 2. There's no like term for the 6b. That means we have:

(7a-8a) - 6b + (7+2) =

-a - 6b + 9

Hope this helps!
6 0
3 years ago
PLEASE HURRY Drag the appropriate estimate to each of the boxes.
Eddi Din [679]

Answer:

please add a photo

Step-by-step explanation:

6 0
2 years ago
X=4y-7<br> 2x+9y=-31 <br> What be the answer
dybincka [34]

Answer:

x=-11

y=-1

Step-by-step explanation:

x=4y-7

2x+9y=-31

2(4y-7)+9y=-31

8y-14+9y=-31

17=-31+14

17y=-17

y=-1

x=4(-1)-7

x=-11

7 0
3 years ago
Read 2 more answers
Find the perimeter of the figure. I’ll mark brainliest if correct
koban [17]

Answer:

66 ft.

Step-by-step explanation:

Add 9+9+9+9+30 and that equals 66.

4 0
2 years ago
Read 2 more answers
Show that cos(3x) = cos3(x) − 3 sin2(x)cos(x). (Hint: Use cos(2x) = cos2(x) − sin2(x) and the cosine sum
otez555 [7]

<u>Step-by-step explanation:</u>

To prove:

\cos 3x=\cos^3x-3\sin^2 x\cos x

Identities used:

\cos(A+B)=\cos A\cos B+\sin A\sin B      ......(1)

\sin 2A=2\sin A\cos A        ........(2)

\cos 2A=\cos^2A-\sin^2 A     .......(3)

Taking the LHS:

\Rightarrow \cos 3x=\cos (x+2x)

Using identity 1:

\Rightarrow \cos (x+2x)=\cos x\cos 2x-\sin x\sin 2x

Using identities 2 and 3:

\Rightarrow \cos x(\cos ^2x-\sin^2 x)-\sin x(2\sin x\cos x)\\\\\Rightarrow \cos^3x-\sin^2x\cos x-2\sin^2 x\cos x\\\\\Rightarrow \cos^3x-3\sin^2x\cos x

As, LHS = RHS

Hence proved

4 0
3 years ago
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