Who studied heredity and is known as the father of Genetics? (I am not surrre lol)

A student needed to make a 3 g/L NaCl solution. The student weighed 3 g of NaCl in a beaker and measured 1 L of water in a 1L vo

hoa [83]

Answer:

The answer is in the explanation.

Explanation:

A solution is defined as the <em>homogeneous mixture </em>of a solute (In this case, NaCl) and the solvent (water).

To prepare 1L of the solution, the student can weigh the 3g of NaCl in the volumetric flask but need to add slowly water to dissolve the NaCl (That is very soluble in water). When all NaCl is dissolved the student must transfer the solution to the 1L volumetric flask. Then, you must add more water to the beaker until "Clean" all the solute of the beaker to transfer it completely to the volumetric flask.

8 0

2 years ago

Which of the following is usually done last in the scientific method of investigation?

Kitty [74]

The answer is C because you must do all the other things first to get to the that’s part hope that helps

8 0

3 years ago

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When butane burns completely, only water and carbon dioxide gas are produced. If 11.6 g of butane and 40.0 L of oxygen at 22.0o

Angelina_Jolie [31]

19.7 litre volume of carbon dioxide gas at 22.0o C and 102 kPa can be collected over water.

<h3>What is vapour pressure?</h3>

Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature.

Moles of Butane = mass in grams / molar mass = 11.6 / 58.12 = 0.2

Volume of $O_2$ (V) = 40 liter

Temperature (T) = 22°C = 22 + 273 = 295 K

Pressure (P) = 102 kPa = 102 / 101.325 = 1.007 atm

Moles of $O_2$ (n) can be calculated by ideal gas equation.

PV = nRT

n = 1.007 40 ÷ 0.0821 295 = 1.663

Balanced chemical reaction;

2 $C_4H_10$ + 13 $O_2$ ---> 8 $CO_2$ + 10 $H_2O$

From reaction;

13 moles $O_2$ require 2 moles $C_4H_10$

So, 1.663 moles $O_2$ will require = 2 x 1.663 ÷13 = 0.256 moles of $C_4H_10$

Thus $C_4H_10$ is a limiting reagent. So it will drive the yield of $CO_2$ .

Moles of $CO_2$ produced = (8/2) 0.2 = 0.8 moles

Pressure of $CO_2$ (P) = 102 - 2.24 = 99.76 kPa = 99.76 ÷ 101.325 = 0.985 atm

Applying the ideal gas equation for $CO_2$ ,

PV = nRT

0.985 V = 0.8 0.0821 x 295

V = 19.7 liter

The volume of $CO_2$ produced = 19.7 liter.

Learn more about the vapour pressure here:

brainly.com/question/25699778

#SPJ1

5 0

1 year ago

What happens when a parking lot is built in a wetlands area?

Airida [17]

The ground could sink and sink holes could occur, otherwise the parking lot could simply break apart and wear faster

5 0

3 years ago

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Consider the balanced equation for the following reaction:

Bad White [126]

<u>Answer:</u> The theoretical yield of the lithium chlorate is 1054.67 grams

<u>Explanation:</u>

To calculate the mass for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Actual moles of lithium chlorate = 9.45 moles

Molar mass of lithium chlorate = 90.4 g/mol

Putting values in above equation, we get:

$9.45mol=\frac{\text{Actual yield of lithium chlorate}}{90.4g/mol}\\\\\text{Actual yield of lithium chlorate}=(9.45mol\times 90.4g/mol)=854.28g$

To calculate the theoretical yield of lithium chlorate, we use the equation:

$\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100$

Actual yield of lithium chlorate = 854.28 g

Percentage yield of lithium chlorate = 81.0 %

Putting values in above equation, we get:

$81=\frac{854.28g}{\text{Theoretical yield of lithium chlorate}}\times 100\\\\\text{Theoretical yield of lithium chlorate}=\frac{854.28\times 100}{81}=1054.67g$

Hence, the theoretical yield of the lithium chlorate is 1054.67 grams

7 0

2 years ago