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MrRa [10]
4 years ago
5

Find x so the distance between (x,2) and (1,5) is 13.

Mathematics
1 answer:
Dmitrij [34]4 years ago
6 0
A(x_1;\ y_1);\ B(x_2;\ y_2)\\\\|AB|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\----------------\\\sqrt{(1-x)^2+(5-2)^2}=13\\(1-x)^2+3^2=169\\(1-x)^2=169-9\\(1-x)^2=160\\1-x=\pm\sqrt{160}\\-x=\pm\sqrt{16\times10}-1\\-x=\pm4\sqrt{10}-1\\\boxed{x=1\pm4\sqrt{10}}


\sqrt{(1-x)^2+(5-2)^2}=\sqrt{13}\\(1-x)^2+3^2=13\\(1-x)^2=13-9\\(1-x)^2=4\\1-x=\pm\sqrt4\\-x=\pm2-1\\-x=-2-1\ or\ -x=2-1\\-x=-3\ or\ -x=1\\\boxed{x=3\ or\ x=-1}

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Answer:

The correct option is d.

Step-by-step explanation:

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Step-by-step explanation:

5 0
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4 0
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astraxan [27]
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step-by-step explanation:

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8 0
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