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zysi [14]
3 years ago
7

Calculate the density of a rod of metal in g/cm3, with a mass of 9.58g, a diameter of 8 mm and a height of 3.5cm

Physics
1 answer:
Ganezh [65]3 years ago
8 0

Answer:

5.448 g/cm³

Explanation:

Density: This is defined as the ratio of the mass of a body to its volume.

The unit of density is kg/m³ other sub units are g/cm³, mg/mm³.

From the question,

D = m/πr²h......................... Equation 1

Where D = density, m = mass, r = radius, h = height.

Given: m = 9.58 g, r = 8/2 mm = 4 mm = 0.4 cm, h = 3.5 cm

Substitute this values into equation 1

D = 9.58/(3.14×0.4²×3.5)

D = 5.448 g/cm³

Hence the density of the metal rod is 5.448 g/cm³

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A watermelon is blown into three pieces by a large firecracker. Two pieces of equal mass m fly away perpendicular to one another
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Answer:

Speed of larger piece is \dfrac{V\sqrt{2}}{3}

Explanation:

We apply the principle of conservation of momentum.

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After the collision,

Vertical momentum = momentum of piece in y-direction + y-component of momentum of larger piece = mV + 3mv_{ly}

Here, v_{ly} is the y-component of velocity of larger piece.

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Here, v_{lx} is the x-component of velocity of larger piece.

This is also equal to 0, since the initial momentum is 0.

v_{lx}=\dfrac{V}{3}

The velocity of the larger piece, v_l, is the resultant of v_{lx} and v_{ly}. Since they are mutually perpendicular,

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3 0
3 years ago
Two wooden crates rest on top of one another. The smaller top crate has a mass of m1 = 21 kg and the larger bottom crate has a m
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Answer:

2.35 m/s²

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We know that the sum of all forces for the two objects with a force of friction F and a tension T are:

(i) m₁a₁ = F

(ii) m₂a₂ = T - F, where m and a are the masses and accelerations respectively.

1) no sliding can also mean that:

a₁ = a₂ = a

This makes us merge the two equations written above together as:

m₂a = T - m₁a

If we then solve for a, we would have something like this

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3 years ago
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