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ad-work [718]
3 years ago
13

A step-up transformer is connected to a generator that is delivering 141 V and 110 A. The ratio of the turns on the secondary to

the turns on the primary is 1110 to 5. What voltage is across the secondary
Physics
1 answer:
hammer [34]3 years ago
5 0

Answer:

31302 Volts and 55/111 Amps (≈0.5)

Explanation:

Secondary voltage / 141 = 1110 / 5

Secondary voltage = (1110*141) / 5

Secondary voltage = 31302

Amperage = 110/ (31302/141) = 55/111

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2144.66 cm³

Explanation:

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3 years ago
There are four charges, each with a magnitude of 2.06 µC. Two are positive and two are negative. The charges are fixed to the co
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Answer:

0.208 N

Explanation:

We are given that

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Net force,F_{net}=\sqrt{F^2_1+F^2_3+2F_1F_3cos90^{\circ}}-F_2

F_1=F_3=F

F_{net}=\sqrt{F^2+F^2+0}-F_2

F_{net}=\sqrt 2F-F_2

F=\frac{kq^2}{d^2}

F_2=\frac{Kq^2}{2d^2}

F_{net}=\frac{\sqrt 2kq^2}{d^2}-\frac{kq^2}{2d^2}=\frac{kq^2}{d^2}(\sqrt 2-\frac{1}{2})

Where k=9\times 10^9

F_{net}=\frac{9\times 10^9\times (2.06\times 10^{-6})^2}{(0.41)^2}(\sqrt 2-\frac{1}{2})

F_{net}=0.208 N

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2 years ago
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Given that,

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The vertical component of velocity is v sinθ

So, vertical component is given by :

v_y=v\ sin(25)

v_y=22\ m/s\times\ sin(25)

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