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N76 [4]
1 year ago
13

In a photoelectric effect experiment, electrons emerge from a copper surface with a maximum kinetic energy of1.10eVwhen light sh

ines on the surface. The work function of copper is4.65eV. Which one of the following values is closest to the wavelength of the light?(h=6.626×10 −34J⋅s=4.141×10 −15eV⋅s,c=3.00×10 8m/s,1eV=1.60×10 −19J)A 360​nmB 1​220 nmC 1100​nm 0⋅150 nm
Physics
1 answer:
V125BC [204]1 year ago
5 0

5.610^-26 m  is closest to the wavelength of the light.

E=K.E - Work function

hc/λ=1.10-4.65

hc/λ=3.50

λ=hc/3.50

λ=6.626×10 −34J⋅s×3×10^8

λ=5.610^-26 m

Because the relationship between wave frequency and wavelength is inverse, gamma rays have extremely short wavelengths that are only a fraction of the size of atoms, whereas other wavelengths can reach as far as the universe. Regardless of the medium they travel through, electromagnetic radiation's wavelengths are typically expressed in terms of the vacuum wavelength, even though this isn't always stated explicitly.

The wavelength of electromagnetic radiation affects its behavior. The speed of light is equal to wavelength times frequency. Frequency multiplied by the Planck constant equals energy. 1/wavelength is the wave number in cm. Along with the wavelengths of different parts of the electromagnetic spectrum, a rough estimation of the wavelength size is displayed.

To know more about  wavelength visit : brainly.com/question/14530620

#SPJ4

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Answer:

\frac{R}{1} = \frac{44}{9}\ohm

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\frac{1}{R} = \frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

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dexar [7]

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Explanation:

From the question given above, the following data were obtained:

Height (h) reached = 1.45 m

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Next, we shall determine the time taken for the kangaroo to return from the height of 1.45 m. This can be obtained as follow:

Height (h) = 1.45 m

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1.45 = ½ × 9.8 × t²

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Divide both side by 4.9

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Finally, we shall determine the total time spent by the kangaroo before returning to the earth. This can be obtained as follow:

Time (t) taken to reach the height = 0.54 s

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T = 2t

T = 2 × 0.54

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Therefore, it will take the kangaroo 1.08 s to return to the earth.

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