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N76 [4]
1 year ago
13

In a photoelectric effect experiment, electrons emerge from a copper surface with a maximum kinetic energy of1.10eVwhen light sh

ines on the surface. The work function of copper is4.65eV. Which one of the following values is closest to the wavelength of the light?(h=6.626×10 −34J⋅s=4.141×10 −15eV⋅s,c=3.00×10 8m/s,1eV=1.60×10 −19J)A 360​nmB 1​220 nmC 1100​nm 0⋅150 nm
Physics
1 answer:
V125BC [204]1 year ago
5 0

5.610^-26 m  is closest to the wavelength of the light.

E=K.E - Work function

hc/λ=1.10-4.65

hc/λ=3.50

λ=hc/3.50

λ=6.626×10 −34J⋅s×3×10^8

λ=5.610^-26 m

Because the relationship between wave frequency and wavelength is inverse, gamma rays have extremely short wavelengths that are only a fraction of the size of atoms, whereas other wavelengths can reach as far as the universe. Regardless of the medium they travel through, electromagnetic radiation's wavelengths are typically expressed in terms of the vacuum wavelength, even though this isn't always stated explicitly.

The wavelength of electromagnetic radiation affects its behavior. The speed of light is equal to wavelength times frequency. Frequency multiplied by the Planck constant equals energy. 1/wavelength is the wave number in cm. Along with the wavelengths of different parts of the electromagnetic spectrum, a rough estimation of the wavelength size is displayed.

To know more about  wavelength visit : brainly.com/question/14530620

#SPJ4

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It is correct to say that impulse is equal toA) momentum.B) the change in momentum.C) the force multiplied by the distance the f
goldenfox [79]

Answer:

B) the change in momentum

Explanation:

Impulse is defined as the product between the force exerted on an object (F) and the contact time (\Delta t)

I=F \Delta t

Using Newton's second law (F = ma), we can rewrite the force as product of mass (m) and acceleration (a):

I=(ma) \Delta t

However, the acceleration is the ratio between the change in velocity (\Delta v) and the contact time (\Delta t): a=\frac{\Delta v}{\Delta t}, so the previous equation becomes

I=m \frac{\Delta v}{\Delta t}\Delta t

And by simplifying \Delta t,

I=m \Delta v

which corresponds to the change in momentum of the object.

8 0
3 years ago
Sound waves require a ________ to travel through
Karolina [17]

Answer:

sound Requires a medium in order to travel.

7 0
3 years ago
Read 2 more answers
You need to focus a 10 mW, 632.8 nm Gaussian laser beam that is 5.0 mm in diameter into a sample. You have access to a lens with
Anna [14]

Answer:

ee that the lens with the shortest focal length has a smaller object

           

Explanation:

For this exercise we use the constructor equation or Gaussian equation

        \frac{1}{f}  = \frac{1}{p} + \frac{1}{q}

where f is the focal length, p and q are the distance to the object and the image respectively.

Magnification a lens system is

          m = \frac{h'}{h} = - \frac{q}{p}

             h ’= -\frac{h q}{p}

In the exercise give the value of the height of the object h = 0.50cm and the position of the object p =∞

Let's calculate the distance to the image for each lens

f = 6.0 cm

           \frac{1}{q} = \frac{1}{f }  - \frac{1}{p}

as they indicate that the light fills the entire lens, this indicates that the object is at infinity, remember that the light of the laser rays is almost parallel, therefore p = inf

          q = f = 6.0 cm

for the lens of f = 12.0 cm q = 12.0 cn

to find the size of the image we use

           h ’= h q / p

where p has a high value and is the same for all systems

           h ’= h / p q

Thus

f = 6 cm h ’= fo 6 cm

 

f = 12 cm h ’= fo 12  cm

therefore we see that the lens with the shortest focal length has a smaller object

8 0
3 years ago
Watching television, with theremote control in your hand, which of the following exerts the greatest gravitational force on you?
natulia [17]
A. The couch you are sitting on
3 0
3 years ago
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How much will the kinetic energy of a school bus increase if its velocity is tripled?
son4ous [18]

Answer:

Explanation:

Given a school bus.

Let say initially the school bus is traveling with speed "v"

Let assume mass of school bus is "m"

Then, the initial kinetic energy is

K.E_initial = ½mv²

Now, if the initial velocity is tripled,

Then, the new velocity is

v_new = 3v.

Note: the mass of the school does not change it is constant

Then, new kinetic energy is

K.E_new = ½m(v_new)²

v_new = 3v

Then,

K.E_new = ½m(3v)²

K.E_new = ½m × 9v²

K.E_new = 9 × ½mv²

Since K.E = ½mv²

Then,

K.E_new = 9 × K.E

So, the new kinetic energy will be 9 times the initial kinetic energy.

So, option D is correct

D. It will be nine times greater.

4 0
3 years ago
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