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solniwko [45]
2 years ago
15

Solve x-3y+2z=1 -x+4y-4z=1 5x-y+6z=9

Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
3 0

Answer:

x=3, y=0, z=-1

Step-by-step explanation:

hope this helped :)

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Answer:

4.67×10^6  is the correct answer

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What is the value of v
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v=9

Step-by-step explanation:

12v-44+6v+23+15v-9+v+30+6v=360

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6 0
2 years ago
The National Center for Health Statistics (NCHS) reports that 70%70% of U.S. adults aged 6565 and over have ever received a pneu
Marianna [84]

Answer:

11.44% probability that exactly 12 members of the sample received a pneumococcal vaccination.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they received a pneumococcal vaccination, or they did not. The probability of an adult receiving a pneumococcal vaccination is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

70% of U.S. adults aged 65 and over have ever received a pneumococcal vaccination.

This means that p = 0.7

20 adults

This means that n = 20

Determine the probability that exactly 12 members of the sample received a pneumococcal vaccination.

This is P(X = 12).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 12) = C_{20,12}.(0.7)^{12}.(0.3)^{8} = 0.1144

11.44% probability that exactly 12 members of the sample received a pneumococcal vaccination.

3 0
2 years ago
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3 0
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choli [55]

Answer:

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14x²-8x+33

7 0
2 years ago
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