Solve x-3y+2z=1 -x+4y-4z=1 5x-y+6z=9
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The number of advance tickets sold is 25 and same day tickets sold is 30.
Data Given;
- Advance Ticket = $30
- Same-day Ticket = $25
- Total Ticket = $60
- Total Cost of Ticket = $1625
Let the number of advance ticket be represented by x
Let the number of same-day ticket be represented by y
From the system of equations above, we can easily pick any to start our calculation.
Using equation (i),
x + y = 60
x = 60 - y ...equation(iii)
Put equation (iii) into equation (ii)
Put the value of y into equation (i)
From the calculation above, the number of advance tickets sold is 25 and same-day tickets is 30.
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