Hey there!
Get molar mass of C₆H₁₀S:
C: 6 x 12.01
H: 10 x 1.008
S: 1 x 32.065
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144.205 g
To find the amount of moles we have, divide 22.4 by 144.205. Get 0.155.
There are 0.155 moles of S.
Hope this helps!
Atomic mass of sodium is 22.9 g/mol
atomic mass of chloride is 35.45 g/mol
sodium chloride is 22.99 + 35.45= 58.44 g/mol
the final concentration of NaI solution in 60 grams/litre.
Explanation:
Given that:
Initial concentration of NaI solution M1 = 0.2 M
initial volume of NaI V1 = 2 L
Final volume V2 = 1 Litre
Final molarity=?
concentration in grams/litre = ?
molar mass of NaI = 150 gram/mole
For dilution following formula is used:
M1 V1 = M2V2
putting the values in the equation
0.2 X 2 = 1 X M2
M2 = 0.4
For concentration in grams/litre, formula used
molarity =
mass = 0.4 x 150
= 60 grams
So, 60 grams of NaI will be present in final solution of NaI after evaporation.
The concentration is 60 grams/ L (as volume got reduced to 1 litre from 2 litres)
1.) when components are needed to be used in different ways
2.) sublimation, filtration, evaporation, and distillation