The half-life of a certain element is 100 days. How many half-lives will it be before only one-eighth of this element remains?
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Answer:
82.28g
Explanation:
Given parameters:
Number of moles of hydrogen gas = 7.26 moles
Unknown:
Amount of ammonia produced = ?
Solution:
We have to write the balanced equation first.
N₂ + 3H₂ → 2NH₃
Now, we work from the known to the unknown;
3 moles of H₂ will produce 2 moles of NH₃
7.26 mole of H₂ will produce = 4.84 moles of NH₃
Molar mass of NH₃ = 14 + 3(1) = 17g/mol
Mass of NH₃ = number of moles x molar mass = 4.84 x 17 = 82.28g