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Len [333]
3 years ago
7

The emissivity of galvanized steel sheet, a common roofing material, is 0.13 at temperatures around 300 K, while its absorptivit

y for solar irradiation is S 0.65. Would the neighborhood cat be comfortable walking on a roof constructed of the material on a day when GS 750 W/m2, T 16 C, and h 7 W/m2 K? Assume the bottom surface of the steel is insulated.
Physics
1 answer:
vfiekz [6]3 years ago
4 0

Answer:

Total heat transfer rate is combined convection and radiation transfer rate, multiplied with absorptivity factor. From that equation you can find temperature of the roof using iteration method.  

Explanation:

<u>Known:</u>

steel sheet roof emissivity ∈ = 0.13

steel sheet roof absorptivity \alpha_s = 0.65

air temperature T∞ = 16°C ...= 289K

heat transfer rate G_s = 750 W/m2

natural convection h = 7W/m2K

Total heat transfer rate is combined heat transfer rate of convection and radiation, multiplied with absorptivity factor:  

\alphaG_s=q_{conv} +q_{rad} =hA(T∞-T_m)+∈σA(T_{surf} -T_{s} )

\alphaG_s-h(T_s-T∞)-∈σ(T_{s} -T_{surf} )=0

2562-7T_s-7.371*10^-9=0

Use iteration method to solve for T_s

T_s=350.17 K...=77.17°C

In this particular situation, cat would not be comfortable with walking on a roof since its surface temperature is 77.17°C which may even cause burns to its paws.  

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