Average speed = (distance covered) / (time to cover the distance)
= (200 miles) / (5.5 hours)
= (200/5.5) mile/hour
= 36.4 miles per hour (rounded)
So we know coefficient of f times normal force is friction. So do 100= .25 times x. Now solve for x. You get 400. So 400 is the normal force. And we know normal force equals weight in these types of problems so the answer is 400
Answer:
0.75 NC⁻¹
Explanation:
Electric field intensity ( or strength of the electric field ) is the force per a 1 C charge,
So, Force (F) = Electric field intensity(E) × Charge (q)
F = E×q ⇒ q = F/E
= 4.5×10⁻⁴/6×10⁻⁴ = 0.75 NC⁻¹
According to cool om's law electric fields are generated due to charges. When charges are same there is a repulsive force acted on both charges. When charges are opposite there is a attraction force acted on both charges.
According to cool om's law,
F =G×q1×q2 / r²
F = force exerted of two charges
q1 , q2 = charges
r = distance between two charges
And also Electric field intensity is a vector which has a magnitude and direction both. Direction is depending on a charge and the sign of the charge
Answer:
A synonym for property is a quality or a characteristic. An antonym is non-physical. A synonym of physical change is a change in state or activity. Phase transition or Natural action.
Explanation:
It is given that a particle covers 10m in first 5s and 10m in next 3s. so using the equation of motion
Case I
s=ut+
2
1
at
2
10=5u+
2
1
a(5)
2
20=10u+25a
4=2u+5a..............(1)
Case 2
In next 3s the particle covers more 10m distance. So
20=8u+
2
1
a(8)
2
5=2u+8a.........(2)
On solving equation (1) and (2)
4=2u+5a
5=2u+8a
a=
3
1
m/s
2
Put the value of a in equation (1)
u=
6
7
m/s
Now to find distance in next 10 s. total time will be 10s
s=
6
7
×10+
2
1
×
3
1
×(10)
2
s=28.33m
Distance travelled in next 2 sec
s=28.33−20=8.33m