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MAXImum [283]
3 years ago
9

A positive charge of 6.0 × 10-4 C is in an electric field that exerts a force of 4.5 × 10-4 N on it. What is the strength of the

electric field?
Physics
2 answers:
VLD [36.1K]3 years ago
6 0

Answer:

0.75 NC⁻¹

Explanation:

Electric field intensity ( or strength of the electric field ) is the force per a 1 C charge,

So, Force (F) = Electric field intensity(E) × Charge (q)

                 F = E×q ⇒ q = F/E

                                      = 4.5×10⁻⁴/6×10⁻⁴ = 0.75 NC⁻¹

According to cool om's law electric fields are generated due to charges. When charges are same there is a repulsive force acted on both charges. When charges are opposite there is a attraction force acted  on both charges.

According to cool om's law,

F =G×q1×q2 / r²

F = force exerted of two charges

q1 , q2 = charges

r = distance between two charges

And also Electric field intensity is a vector which has a magnitude and direction both. Direction is depending on a charge and the sign of the charge

Sidana [21]3 years ago
6 0

Answer:

0.75 on edge 2020

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Given the two definitions, equipotential lines are always perpendicular to the electric field lines. Therefore, in this problem, the direction of the electric field is perpendicular to the spherical equipotential surface.

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