Newton's 2nd law:
Fnet = ma
Fnet is the net force acting on an object, m is the object's mass, and a is the acceleration.
The electric force on a charged object is given by
Fe = Eq
Fe is the electric force, E is the electric field at the point where the object is, and q is the object's charge.
We can assume, if the only force acting on the proton and electron is the electric force due to the electric field, that for both particles, Fnet = Fe
Fe = Eq
Eq = ma
a = Eq/m
We will also assume that the electric field acting on the proton and electron are the same. The proton and electron also have the same magnitude of charge (1.6×10⁻¹⁹C). What makes the difference in their acceleration is their masses. A quick Google search will provide the following values:
mass of proton = 1.67×10⁻²⁷kg
mass of electron = 9.11×10⁻³¹kg
The acceleration of an object is inversely proportional to its mass, so the electron will experience a greater acceleration than the proton.
Answer:
0.75Hz
Explanation:
Given parameters:
Speed of the wave = 3m/s
Wavelength = 4m
Unknown:
Frequency of the wave = ?
Solution:
The speed of a wave is given by the expression below:
Speed = frequency x wavelength
Frequency = 
= 
= 0.75Hz
Answer: option A. r = 3x+2y
Explanation:
Vector r is plotted on the graph. On x-axis each small division corresponds to 1 unit. Similarly on y-axis, each small division corresponds to one unit.
The vector is the resultant of addition of its x and y components. we would draw perpendicular to the x-axis and y-axis from the head of vector r.
On x-axis, 
= +3 units
on y-axis, 
= +2 units
Hence, vector r can be written as: r = 3x + 2y . Correct option is A.
The given are:A
djacent/Hypotenuse = sin 35°
Height(h) - Adjacent
Hypotenuse- a length of a side:
We will use the formula:
sin (angle) = op/hyp
sin 35° = h/ 4.1 m
0.57356 = h / 4.1 m
h = 0.576576 ·
4.1 = 2.35166 ≈ 2.4 m
Answer: the top of the slide is 2.4 m above the ground which is letter d.
