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Tpy6a [65]
3 years ago
13

The compound responsible for the characteristic smell of garlic is allicin, c6h10os2. the mass of 1.00 mol of allicin, rounded t

o the nearest integer, is __________ g
Chemistry
1 answer:
Gemiola [76]3 years ago
4 0

The compound responsible for the characteristic smell of garlic is allicin, that is having molecular formula C₆H₁₀OS₂.

Molar mass of C₆H₁₀OS₂=162.26 g mol⁻¹.

number of moles of C₆H₁₀OS₂=1 mol

So mass of C₆H₁₀OS₂ can be calculated as:


Number of moles of C_{6}H_{10}OS_{2}, n= \frac{Given mass of the }{Molar mass of theC_{6}H_{10}OS_{2}}

1= \frac{Given mass of the C_{6}H_{10}OS_{2}}{162.26}

Given mass of the C₆H₁₀OS₂= 162 g


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What is the percentage of water in hydrated calcium chloride​
earnstyle [38]

Answer:

24.5%

Explanation:

You just add up the atomic masses.  

Ca - 40.078  

Cl2 - 35.4527 x 2 = 70.9054  

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H4 - 1.00794 x 4 = 4.03176  

O2 - 31.9998  

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So the water is 36.03056/147.01396 = .245082576 but that is only accurate to three decimals (because the mass of Ca was only given to three decimals) so we write .245 and that is 24.5%

This is not my answer but I found it on Yahoo answers and it was answered by Anonymous.

8 0
3 years ago
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A mixture of c2h2 and ch4 has a total mass of 230.9 g. when this mixture reacts completely with excess oxygen, the co2 and h2o p
Salsk061 [2.6K]
Interesting problem. Thanks for posting.

C2H2 + (3/2)02 ====>  H2O + 2CO2
CH4 +  2O2 =====> 2H2O + CO2

The molar mass of C2H2 = 2*12 + 2*1 = 26
The molar mass of CH4 = 1*12 + 4*1 = 16

The number of moles of C2H2 = x
The number of moles of  CH4 = y
26x + 16y = 230.9 grams

For water we get (from the C2H2). Water has a molar mass of 2*1 + 16 = 18

x*18 See the balanced equation to see what it is the same number of moles as C2H2
From the methane we get
y*18
2*y* 18. Again see the balanced equation to see where that 2 came from.
18x + 36y is the total amount of water. 

Now for the CO2. CO2 has a molar mass of 12 + 2*16 = 44
From C2H2  we get 2*44*x = 88x grams of CO2
From CH4 we get 1*y*44 grams of CO2
88x + 44y for CO2

Now we total to get the grand total of water and CO2
18x + 44y + 88x + 44y = 972.7 grams total.
106x + 88y =  972.7

Two equations, two unknowns, we should be able to solve this problem
26x + 16y = 230.9
106x + 88y = 972.7

I'm not going to go through the math unless you request me to do so. 
x = 8.03 moles
y = 1.38 moles 

The initial amount of C2H2 was 8.03 * 26 = 208.78
The initial amount of CH4 was 16*1.38 = 22.08
The total (as a check is 230.86 which is pretty close to the given amount.
So Methane's mass in the initial givens was 22.08 grams.
6 0
3 years ago
The half-life of radon-222 is 3.8 days. If a sample currently contains 3.1 grams of radon-222, how much radon-222 did this sampl
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The   number  of grams of  radon 222 did it have 15.2  ago was  49.6 grams( answer  C)

 <u>calculation</u>

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