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lisabon 2012 [21]
3 years ago
12

A metal ion with a net +3 charge has five electrons in the 3d shell. Identify the metal.

Chemistry
2 answers:
ValentinkaMS [17]3 years ago
3 0

<u>Answer:</u> The given metal is iron.

<u>Explanation:</u>

We are given:

The electrons in 3d-shell = 5

When the metal is present in a transition series (here it is present in first transition series), the removal of valence electron takes place from '4s' shell first and then from '3d' shell

Electronic configuration is defined as the representation of electrons around the nucleus of an atom.

Number of electrons in an atom is determined by the atomic number of that atom.

Inner shell electrons for the given element = 18

Total number of electrons in the ion = 18 + 5 = 23

We are given:

Charge on the ion = +3

To calculate the number of electrons, we use the equation:

Number of electrons = Atomic number - charge

Atomic number = 23 + 3 = 26

The element having atomic number '26' is iron

Hence, the given metal is iron.

Sonja [21]3 years ago
3 0

Answer: the metal is Iron (Fe)

Explanation: The original electronic configuration of Fe is 1s2 2s2 2p6 3s2 3p6 3d6 4s2

Because it has no charge. The electronic configuration will change from the original because the metal has a charge of +3, Fe is element number 26 on the periodic table b ut with the +3 charge, the element number will change to 23 i.e 26-(+3) =23

The configuration for Fe3+ is 1s2 2s2 2p6 3s2 3p6 3d5, it automatically had 5 electron in 3d shell

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A ball has a mass of 0.5g and a volume of 10mL. Calculate the density
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0.05g/ml

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In acetyl CoA formation, the carbon-containing compound from glycolysis is oxidized to produce acetyl CoA. From the following co
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Answer:

- Net Input: NAD⁺, coenzyme A, pyruvate

- Net Output: NADH, acetyl CoA, CO₂

- Not input or output: O₂, ADP, glucose and ATP

Explanation:

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In this case, it is important to recall that acetyl-CoA is produced either by oxidative decarboxylation of pyruvate derived from glycolysis, which is carried out into the mitochondrial matrix, by cause of the oxidation of high-order fatty acids, or by oxidative degradation of very specific amino acids. Acetyl-CoA then enters in the citric acid cycle where it is oxidized in the light of energy production.

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- Net Input: NAD⁺, coenzyme A, pyruvate

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8 0
3 years ago
If a student mixes 75 mL of 1.30 M HNO3 and 150 mL of 6.5 M NaOH. is the final solution acidic, basic, or neutral
raketka [301]

Answer:

The solution is basic.

Explanation:

We can determine the nature of the solution via determining which has the large no. of millimoles (acid or base):

  • If no. of millimoles of acid > that of base; the solution is acidic.
  • If no. of millimoles of acid = that of base; the solution is neutral.
  • If no. of millimoles of acid < that of base; the solution is basic.

  • We need to calculate the no. of millimoles of acid and base:

no. of millimoles of acid (HNO₃) = MV = (1.3 M)(75.0 mL) = 97.5 mmol.

no. of millimoles of base (NaOH) = MV = (6.5 M)(150.0 mL) = 975.0 mmol.

<em>∴ The no. of millimoles of base (NaOH) is larger by 10 times than the acid (HNO₃).</em>

<em>So, the solution is: basic.</em>

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