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3 years ago

If a student mixes 75 mL of 1.30 M HNO3 and 150 mL of 6.5 M NaOH. is the final solution acidic, basic, or neutral

Chemistry

1 answer:

raketka [301]3 years ago

4 0

Answer:

The solution is basic.

Explanation:

We can determine the nature of the solution via determining which has the large no. of millimoles (acid or base):

If no. of millimoles of acid > that of base; the solution is acidic.

If no. of millimoles of acid = that of base; the solution is neutral.

If no. of millimoles of acid < that of base; the solution is basic.

We need to calculate the no. of millimoles of acid and base:

no. of millimoles of acid (HNO₃) = MV = (1.3 M)(75.0 mL) = 97.5 mmol.

no. of millimoles of base (NaOH) = MV = (6.5 M)(150.0 mL) = 975.0 mmol.

<em>∴ The no. of millimoles of base (NaOH) is larger by 10 times than the acid (HNO₃).</em>

<em>So, the solution is: basic.</em>

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Hydrogen peroxide, H2O2, is common in many households and is used as a bleaching agent. It usually comes in a dark, opaque bottl

sergij07 [2.7K]

Answer:

Hydrogen peroxide should be stored in

1) a cool environment

2) with amber bottles away from sunlight

3) with little drops of sodium phosphate

Explanation:

It has been confirmed that heat and light aids in the decomposition of hydrogen peroxide according to the equation; 2H2O2→2 H2O + O2.

This means that hydrogen peroxide must be stored in a cool place. This will reduce its rate of decomposition. Secondly, it should be stored in amber bottles away from light since light also aids in its decomposition.

Thirdly, drops of sodium phosphate may be added to prevent its catalytic decomposition during storage.

8 0

4 years ago

Cyclohexane, a commonly used organic solvent, is 85.6% c and 14.4% h by mass with a molar mass of 84.2 g/mol. what is its molecu

puteri [66]

The molecular formula of organic solvent is <em>C6H12</em>

<h2>calculation</h2><h3>find the empirical formula first as in step 1 and 2</h3>

Step 1: f<em>ind the moles of C and H</em>

moles = % composition/molar mass

from periodic table molar mass of C= 12 g/mol while that of H= 1 g/mol
moles is C is therefore = 85.6/12= 7. 13 moles
moles of H= 14.4/1 - 14.4 moles

Step 2: <em>calculate the mole fraction by dividing each mole by smallest number of mole(7.13)</em>

that is C= 7.13/7.13 = 1

H= 14.4/7.13 =2

the empirical formula is therefore = CH2

<h2>Then calculate the molecular formula from empirical formula</h2>

step 3: divide the grams molar mass by empirical formula mass

empirical formula mass = 12+(1 x2) = 14 g/mol

= 84.2/ 14 = 6

step 4: multiply each of the subscript within the empirical formula with the value gotten in step 3

that is [CH2]6 = C6H12 therefore the molecular formula = <u>C6H12</u>

8 0

3 years ago

Consider the electrolysis of molten barium chloride, BaCl2. (a) Write the half-reactions. (b) How many grams of barium metal can

Zielflug [23.3K]

Answer: a) Cathode(-): $Ba^+^2+2e^-\rightarrow Ba$

Anode(+): $2Cl^-\rightarrow Cl_2+2e^-$

b) 0.640 grams of Ba will be deposited.

Explanation: a) The problem is based on Faraday law of electrolysis. Molten barium chloride has $Ba^+^2$ ion and $Cl^-$ ion. Barium ion is reduced and chloride is oxidized. Reduction takes place at cathode and oxidation at anode. So, the half reactions will be:

Cathode(-): $Ba^+^2+2e^-\rightarrow Ba$

Anode(+): $2Cl^-\rightarrow Cl_2+2e^-$

b) The question asks, how many grams of barium metal can be produced by supplying 0.50 ampere for 30 minutes.

From the Cathode half-reaction, 1 mole of Ba is deposited by 2 moles of electrons and we know that 1 mole of electron carries one Faraday that is 96485 Coulomb.

Coulombs for 2 moles of electrons will be = 2*96485 C = 192970 C

So, we can say that, 192970 C will deposit 1 mole of Ba metal.

Total available coulombs can be calculated using the formula:

q=i*t

where, q is electric charge in coulomb, i is current in ampere and t is time in seconds.

$q=q=0.50A*30min(\frac{60sec}{1min})$

q = 900 C (note: 1 C = 1 A*sec)

Let's calculate how many moles of Ba will get deposited by 900 C.

$900C(\frac{1molBa}{192970C})$

= 0.00466 mole Ba

Convert the moles of Ba to grams and for this we multiply by molar mass of Ba which is 137.33 gram per mol.

$0.00466molBa(\frac{137.33g}{1mol})$

= 0.640 g Ba

So, 0.50 A for 30 minutes will deposit 0.640 grams of Ba metal.

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3 years ago

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Papessa [141]

It can be from volcanic ash, or from eroded material transported by rivers or wind.

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3 years ago

Color is not very helpful in mineral itdentification because

matrenka [14]

Some colours appear as white

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3 years ago