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3 years ago

Marvelous rides his bike with a constant speed of 6 miles per hour east. How long will he take to travel 21

Chemistry

1 answer:

ad-work [718]3 years ago

3 0

Answer:

It will take Marvelous 160 miles per hour east to travel 21 miles.

Explanation:

Because 21 times 6= 160 and make sure to add the per hour east because thats the velocity.

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2H2 + O2 + 2H20

kondaur [170]

Answer:

Hello

The answer is 25gr H2O

Explanation:

50grH2×1 molH2/2 gr H2×2mol H2O/2molH2=25gr H2O

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3 years ago

Arrange the following sublevels in order of <br> increasing energy: 3d, 2s, 4s, 3p.

ycow [4]

To arrange the sublevels in order of increasing energy, we add the principal shell and the maximum number of electrons of the specific sublevel. s has 2 electrons, p has 6 electrons, d has 10 electrons, and f and 14 electrons. in this case, a) 3 + 10 = 13b) 2 + 2 = 4c) 4 + 2 = 6d) 3 + 6 = 9
The order hence is 2s, 4s, 3p, and 3d

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3 years ago

A sample of nitrogen gas has a temperature of 22.7oC when the volume of the container is 12.2L and it is under 150.4kPa of press

Marrrta [24]

Answer:

The final temperature of the gas would need to be approximately 158.4 K

Explanation:

The details of the sample of nitrogen gas are;

The initial temperature of the nitrogen gas, T₁ = 22.7°C = 295.85 K

The initial volume occupied by the gas, V₁ = 12.2 L

The initial pressure of the gas, P₁ = 150.4 kPa

The final volume of the gas, V₂ = 9.7 L

The final pressure of the gas, P₂ = 101.3 kPa

Let 'T₂', represent the final temperature of the gas, by the ideal gas equation, we have;

$\dfrac{P_1 \times V_1}{T_1} = \dfrac{P_2 \times V_2}{T_2}$

$\therefore \ T_2 = \dfrac{P_2 \times V_2 \times T_1 }{P_1 \times V_1}$

Plugging in the values gives;

$\therefore \ T_2 = \dfrac{101.3 \, kPa \times 9.7 \ L \times 295.85 K}{150.4 \ kPa \times 12.2 \ L} \approx 158.4327959 \ K$

The final temperature of the gas, T₂ ≈ 158.4 K

3 0

3 years ago

Name this please for me lol

igor_vitrenko [27]

Answer:

1-butene

Explanation:

To name the compound, start counting from the side that gives the double bond the lowest low count since the functional group of the compound is the double.

Now in the name of the compound, we must indicate the position of the double bond.

The name of the compound is butene. But the position of the double is unknown. Since we started counting from the left, the double bond is at carbon 1.

Therefore, the name of the compound is 1-butene

7 0

3 years ago

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ladessa [460]

Answer:

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only one that suggests anything about the sun/solar activity.

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3 years ago

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