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Eddi Din [679]
4 years ago
12

Giselle is working with a chemical substance in a laboratory. She observes that when the chemical is heated, it gives off a gas.

She assumes that the gas is oxygen but decides to test this assumption to verify it. Which type of scientific knowledge is Giselle’s assumption?
A.
fact
B.
hypothesis
C.
law
D.
observation
E.
theory
Chemistry
2 answers:
Phoenix [80]4 years ago
6 0

The correct answer is option B, that is, hypothesis.  

A hypothesis refers to an anticipated illustration for an occurrence. It refers to a proposed illustration or a supposition made on the groundwork of inadequate proof as an initiation point for further investigation. In order for a hypothesis to be a scientific hypothesis, the scientific method needs that one can examine it.  


anzhelika [568]4 years ago
6 0
Her observation was B) a hypothesis
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Sort the steps in the scientific method.
saw5 [17]

Answer:

  1. Interpretation
  2. Investigation
  3. Hypothesis
  4. Conclusion
5 0
3 years ago
14. What is the total number of kilojoules of heat needed to change 150. G of
Nadusha1986 [10]

Answer:

\boxed {\boxed {\sf 50.1 \ kJ}}

Explanation:

When water changes from ice (solid) to water (liquid), it is melting or fusion. Therefore, we can use the following formula to find energy:

q=mH_f

where <em>q</em> is the energy, <em>m </em>is the mass, and <em>Hf</em> is the heat of fusion.

1. Define Values

The mass is 150 grams. The heat of fusion for water is 334 Joules per gram.

m= 150 \ g \\H_f=334 \ J/g

2. Calculate Energy

Substitute the values into the formula.

q=150 \ g * 334 \ J/g

Multiply. Note that the grams (g) will cancel each other out and leave Joules as our units.

q=150 *334 \ J

q=50100 \ J

3. Convert Units

We found the answer in joules, but the question asks for kilojoules, so we must convert.

There are 1000 Joules in 1 kilojoule. Therefore, we can divide the joules calculated by 1000.

50100 \ J *\frac{1 \ kJ}{1000 \ J}

\frac{50100 \ kJ}{1000 \ }

50.1 \ kJ

<u>50.1 kilojoules </u>are needed to change 150 grams of ice to water.

8 0
3 years ago
Identify the gas particle that travels the slowest. ne h2 co n2 o2
Evgen [1.6K]
<span>O2 travels slower than H2, Ne, N2, and CO. This is due to the fact that O2 has a heavier molecular weight than the others. O2 has a weight of 32 grams per mole. N2 and CO are the next highest with 28 grams per mole. Ne is 20 grams per mole, and H2 is 2 grams per mole.</span>
5 0
4 years ago
Read 2 more answers
Thiols, sulfides and disulfides have high solubility in water. a. True b. False
Rudiy27

Answer:

the answer is a true

Explanation:

5 0
3 years ago
When bsia is assembled as an octamer, what is most likely to be true regarding l76, l77, and l79?
telo118 [61]

The option that is most likely to be true regarding L76, L77, and L79  is that option B: The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

<h3>What is entropic penalty?</h3>

The entropic penalty in regards to ordered water is known to be one that tells or account  for any form of  weaker binding of the antibiotic novobiocin to what we call resistant mutant of DNA gyrase.

Note that in regards to the scenario above, the Entropic penalty is seen as the thermodynamically disfavored needs that is required in forming a cage of polar solvent molecules that is known to be seen around surface that has exposed hydrophobic potion of a molecule.

Hence, The option that is most likely to be true regarding L76, L77, and L79  is that option B: The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

Learn more about octamer from

brainly.com/question/13198179

#SPJ1

See full question below

When Bs1A is assembled as an octamer, what is most likely to be true regarding L76, L77, and L79?

A. They are oriented toward the solvent-exposed exterior of the protein assembly.

B. The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

C. Unlike in a monomer, they are not situated within the hydrophobic cap.

D. Their physiochemical properties are not substantially dependent on their hydrophobicity

5 0
2 years ago
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