When sodium carbonate decomposes, it also leaves behind carbon dioxide, or CO2. You can find this out without knowing about carbonate reactions though. Chemical equations must be balanced, so whatever is on the left must also be on the right. There are 2 atoms of sodium, one atom of carbon, and three atoms of oxygon on the left. On the right, there is two atoms of sodium and one atom of oxygen. We are still missing one atom of carbon and one two atoms of oxygen, which, when combined, make a molecule of carbon dioxide.
Answer:
0.625 kg
Explanation:
Since 90.6 is 3 half-lives from 30.2 (90.6/30.2 = 3) , divide the initial mass of the sample by 2, and divide that quotient by 2, and divide THAT quotient by 2 to determine how much remains after 3 half-lives.
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The biggest ocean wave that was ever recorded was 70+ feet tall.
Answer:
2.72g
Explanation:
The balanced equation of this reaction is given as follows:
Na2O + H20 --> 2NaOH
Based on this balanced equation, 1 mole of Na2O will produce 2 moles of NaOH.
First, we need to convert mass of Na2O into moles by using the formula;
mole = mass/molar mass
Molar mass of Na2O = 23(2) + 16
= 46 + 16
= 62g/mol
mole = 2.1g/62g/mol
mole of Na2O = 0.034mol
Hence, if 1 mole of Na2O will produce 2 moles of NaOH.
Then, 0.034mol of Na2O will produce (0.034 × 2) = 0.068mol of NaOH.
To convert mole of NaOH to mass, we use;
mole = mass/molar mass
Molar mass of NaOH = 23 + 16 + 1 = 40g/mol
0.068 = mass/40
mass of NaOH produced = 2.72g.