Answer:
Both are the indicators which helps to identity the acid and base
Haploid number of chromosomes and gamete cells.
Answer:
ΔG° = 2.57 × 10² kJ
The reaction is spontaneous.
Explanation:
<em>The standard cell potential, E°cell, for a reaction in which two electrons are transferred between the reactants is +1.33 V. Calculate the standard free energy change, ΔG°, in kJ for this reaction and determine if it is spontaneous or nonspontaneous at 25°C.</em>
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We can calculate the standard Gibbs free energy (ΔG°) using the following expression.
ΔG° = -n × F × E°cell
where,
n: moles of electrons transferred
F: Faraday's constant
E°cell: standard cell potential
ΔG° = - (2 mol) × (96468 J/V . mol) × 1.33 V
ΔG° = -2.57 × 10⁵ J = 2.57 × 10² kJ
ΔG° < 0 means that the reaction is spontaneous.
Answer:
173.8g
Explanation:
STP means standard temperature and pressure
The temperature there is 273k while the pressure is 1 atm
now we are to use the ideal gas equation to get the number of moles first
Mathematically;
PV = nRT
here P = 1 atm
V = 88.5 L
n = ?
R = molar gas constant = 0.082 L atm mol^-1 K^-1
Now rewriting the equation we can have
n = PV/RT
plugging the values we have
n = (1 * 88.5)/(0.082 * 273)
n = 88.5/22.386
n = 3.95 moles
Now we proceed to get the mass
Mathematically;
mass = no of moles * molar mass
molar mass of carbon iv oxide is 44g/mol
mass = 3.95 * 44 = 173.8 g
Answer:
I can use a dichotomous key. It helps me classify objects by sorting it out with "yes" and "no" questions.
or
I can use a Punnett Square. It helps me classify what genes the offspring will receive simply by figuring out the recessive and dominant genes as well as the hetzygous and homzygous.
Now give an example of which ever chart you choose by drawing it if that is required. For the Punnett Square label each of the squares Top right Hetzygous, top left dominant, bottom left recessive, bot-tom right homzygous. And for the dichotomous key put a 5-7 length branch showing the animals that have fur, can breathe under water, what cannot or doesn't have those traits. or something similar
Hopefully this helps :)
