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Klio2033 [76]
3 years ago
10

What is angle A on a right triangle with sides AB being 6 and side CB being 4

Mathematics
1 answer:
adell [148]3 years ago
4 0

Answer:41.8

Step-by-step explanation:

a=4

c=6

C=90

Applying sine rule :

a/sinA = c/sinC

4/sinA=6/sin90 sin90=1

4/sinA=6/1

Cross multiplying we get

4 x 1=6 x sinA

4=6sinA

divide both side by 6

4/6=(6sinA)/6

4/6=sinA

sinA=4/6

A=sin(inverse)(4/6)

A=41.8

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