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kati45 [8]
3 years ago
13

ball is dropped from a height of 1.60 m and rebounds to a height of 1.20 m. Approximately how many rebounds will the ball make b

efore losing 90% of its energy?
Physics
1 answer:
jasenka [17]3 years ago
3 0

Answer:

the ball rebounds 8 times before losing 90% of its energy

Explanation:

given information:

height, h₁ = 1.6 m

rebound height, h₂ = 1.2 m

energy loss = 90% = 0.9

first we can calculate the loss energy after the rebound

energy loss = 1 - [(height of rebound/height of the ball)^n

where

n = number of the bounce

energy loss = 1 - (h₂/h₁)^n

0.9 = 1 - (1.2/1.6)^n

(0.75)^n = 1 - 0.9

n log 0.75 = log 0.1

n = log 0.1/log 0.75

  = 8 bounces

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Master of physics needed
Delicious77 [7]
Hey JayDilla, I get 1/3.  Here's how:
Kinetic energy due to linear motion is:
E_{linear}= \frac{1}{2}mv^2
where
v=r \omega
giving
E_{linear}= \frac{1}{2}mr^2 \omega ^2

The rotational part requires the moment of inertia of a solid cylinder
I_{cyl} =  \frac{1}{2}mr^2
Then the rotational kinetic energy is
E_{rot}= \frac{1}{2}I \omega ^2= \frac{1}{4}mr^2 \omega ^2
Adding the two types of energy and factoring out common terms gives
\frac{1}{2}mr^2 \omega ^2(1+ \frac{1}{2})
Here the "1" in the parenthesis is due to linear motion and the "1/2" is due to the rotational part.  Since this gives a total of 3/2 altogether, and the rotational part is due to a third of this (1/2), I say it's 1/3.

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4 years ago
Choose the false statement regarding resistance.
Afina-wow [57]

Answer:

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3 years ago
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<span>B. velocity .................</span>
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3 years ago
How long was a 60 W light bulb turned on if it used a total of 580 J of energy?
icang [17]
Here's the tool you need.  You can't answer the question without this:

           "1 watt"
means
           "1 joule of energy, generated, used, or moved, every second".

So      60 watts  =  60 joules per second

           Total energy generated,
            used, or moved                  = (power) x (time).

                                     580 joules  =  (60 watts) x (time)

Divide each side
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