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kati45 [8]
3 years ago
13

ball is dropped from a height of 1.60 m and rebounds to a height of 1.20 m. Approximately how many rebounds will the ball make b

efore losing 90% of its energy?
Physics
1 answer:
jasenka [17]3 years ago
3 0

Answer:

the ball rebounds 8 times before losing 90% of its energy

Explanation:

given information:

height, h₁ = 1.6 m

rebound height, h₂ = 1.2 m

energy loss = 90% = 0.9

first we can calculate the loss energy after the rebound

energy loss = 1 - [(height of rebound/height of the ball)^n

where

n = number of the bounce

energy loss = 1 - (h₂/h₁)^n

0.9 = 1 - (1.2/1.6)^n

(0.75)^n = 1 - 0.9

n log 0.75 = log 0.1

n = log 0.1/log 0.75

  = 8 bounces

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Could you please assist me, thank you kindly.
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In Newton's Third law of motion, the 'action' and 'reaction' forces act on different objects.  That's why they don't cancel each other out and always result in zero force.

4 0
3 years ago
A train accelerates from 23m/s to 190m/s in 54 seconds. What was its acceleration?
Ierofanga [76]

Answer:

Use the method on the image and solve it.

3 0
4 years ago
When are all the forces acting upon an object balanced?
Rudik [331]

Answer:

When two forces acting on an object are equal in size but act in opposite directions, we say that they are balanced forces.

Explanation:

7 0
3 years ago
An airplane with a mass of 5,000 kg needs to accelerate 5 m/s2 to take off before it reaches the end of the runway. How much for
Anastasy [175]

Answer:

<h2>25000 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 5000 × 5

We have the final answer as

<h3>25000 N</h3>

Hope this helps you

6 0
3 years ago
Consider the following three objects, each of the same mass and radius: (1) a solid sphere (2) a solid disk (3) a hoop All three
Vinil7 [7]

Answer:

The correct answer is

a) 1, 2, 3

Explanation:

In rolling down an inclined plane, the potential energy is Transferred to both linear and rotational kinetic energy thus

PE = KE or mgh = 1/2×m×v² + 1/2×I×ω²

The transformation equation fom potential to kinetic energy is =

m×g×h = \frac{1}{2} mv^{2} + \frac{1}{2} (\frac{2}{5} mr^{2} )(\frac{v}{r}) ^{2}

v_{Sphere} = \sqrt{\frac{10}{7} gh}

v_{Hoop} = \sqrt{gh}

v_{Disc}=\sqrt{\frac{4}{3} gh}

Therefore the order is with increasing rotational kinetic energy hence

the first is the sphere 1 followed by the disc 2 then the hoop 3

the correct order is a, 1, 2, 3

8 0
4 years ago
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