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kati45 [8]
3 years ago
13

ball is dropped from a height of 1.60 m and rebounds to a height of 1.20 m. Approximately how many rebounds will the ball make b

efore losing 90% of its energy?
Physics
1 answer:
jasenka [17]3 years ago
3 0

Answer:

the ball rebounds 8 times before losing 90% of its energy

Explanation:

given information:

height, h₁ = 1.6 m

rebound height, h₂ = 1.2 m

energy loss = 90% = 0.9

first we can calculate the loss energy after the rebound

energy loss = 1 - [(height of rebound/height of the ball)^n

where

n = number of the bounce

energy loss = 1 - (h₂/h₁)^n

0.9 = 1 - (1.2/1.6)^n

(0.75)^n = 1 - 0.9

n log 0.75 = log 0.1

n = log 0.1/log 0.75

  = 8 bounces

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\omega = \sqrt{\frac{k}{m}

Given the expressions;

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Equating both expressions we will have;

2 \pi \sqrt{\frac{m}{k} }  = \frac{2 \pi}{\omega}

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3 years ago
The length of a cylindrical axon is 8 cm and its radius of 8μm,and the thickness of the membrane is 0.01μm,dielectric constant (
GuDViN [60]

Answer:

9.965 nF

Explanation:

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So, C = εA/d

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Substituting the of the values variables into the equation, we have

C = ε2πrL/d

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C =  9964.63 × 10⁻²⁰ Fm/0.01 × 10⁻⁶ m

C =  996463 × 10⁻¹⁴ F

C = 9.96463 × 10⁻⁹ F

C = 9.96463 nF

C ≅ 9.965 nF

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