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Yakvenalex [24]
3 years ago
15

What are possible formulas for impulse? Check all that apply.

Physics
2 answers:
iris [78.8K]3 years ago
7 0
<span> J = Ft, J = mv and J = p</span>
iren2701 [21]3 years ago
3 0
<h2>Formulas For Impulse </h2>

Impulse is the variance of the momentum of a thing when the thing is operated upon by a force for an interval of time. Following are the possible formulas for impulse as;

Momentum is product of mass and velocity. According to newton’s second law, F =ma is by putting values of acceleration (a = ( vf - vi ) / t. Therefore, F =( m v ) / t. F t = m v and F t is impulse.

J = Ft

J = mv

J = p

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Read 2 more answers
A pitcher throws a 0.140 kg baseball, and it approaches the bat at a speed of 35.0 m/s. The bat does Wnc = 75.0 J of work on the
Eva8 [605]

Answer:

The speed of the ball is 42.5 m/s

Explanation:

The initial kinetic energy of the ball is:

K_1=\frac{1}{2} m v_0^2=\frac{1}{2}*0.140 kg*(35.0 m/s)^2= 85.75 J

The speed of the ball after leaving the bat is:

K_2=K_1+W_{nc}\\ \frac{1}{2}mV^2= 85.75 J + 75 J\\ (\frac{1}{2}mV^2)2=( 160.75 J)2\\ mV^2= 321.5 J\\ V^2= \frac{321.5 J}{0.140kg} \\ V=\sqrt{\frac{321.5 J}{0.140kg}}

V=47.92 m/s

Using kinematic equation we can find the speed of the ball after being 25 m above the point of collision:

V_f^2-V^2=-2gh

V_f^2-(47.92 m/s)^2=-2*9.81m/s^2*25m

V_f^2=-2*9.81m/s^2*25m+(47.92 m/s)^2

V_f=\sqrt{-2*9.81m/s^2*25m+(47.92 m/s)^2}

V_f=42.5m/s

3 0
3 years ago
A baseball has a mass of 0. 45 kg and is thrown with a speed of 25 m/s. What is the momentum of the baseball? 0. 018 kg • mete
aleksandr82 [10.1K]

Answer:

11 Kg.m/s

Explanation:

P=mv

P=0.45*25

P=11.25 Kg.m/s

3 0
2 years ago
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