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3 years ago

37. A baseball is pitched at a speed of 40 m/s. How long does it take the ball to travel 27

Physics

2 answers:

OlgaM077 [116]3 years ago

8 0

Answer:

$0.675\:\mathrm{s}$

Explanation:

Displacement can be given as $\Delta x=v_x\cdot t$

Substituting given values, we have:

$27=40t,\\t=\frac{27}{40}=\boxed{0.675\:\mathrm{s}}$

deff fn [24]3 years ago

5 0

Answer:

0.675

Explanation:

hope you get it right

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A rigid tank initially contains 3kg of carbon dioxide (CO2) at a pressure of 3bar.The tank is connected by a valve to a friction

marissa [1.9K]

Answer:

Part a: The total amount of energy transfer by the work done is 54.81 kJ.

Part b: The total amount of energy transfer by the heat is 54.81 kJ

Explanation:

Mass of Carbon Dioxide is given as m1=3 kg

Pressure is given as P1=3 bar =300 kPA

Volume is given as V1=0.5 m^3

Pressure in tank 2 is given as P2=2 bar=200 kPa

T=290 K

Now the Molecular weight of $CO_2$ is given as

M=44 kg/kmol

the gas constant is given as

$R=\frac{\bar{R}}{M}\\R=\frac{8.314}{44}\\R=0.189 kJ/kg.K$

Volume of the tank is given as

$V=\frac{mRT}{P_1}\\V=\frac{3 \times 0.189 \times 290}{300 }\\V=0.5481 m^3$

Final mass is given as

$m_2=\frac{P_2V}{RT}\\m_2=\frac{200\times 0.5481}{0.189\times 290}\\m_2=2 kg$

Mass of the CO2 moved to the cylinder

$m=m_1-m_3\\m=3-2=1 kg$

The initial mass in the cylinder is given as

$m_{(cyl)_1}=\frac{P_{(cyl)_1}V_1}{RT}\\m_{(cyl)_1}=\frac{200\times 0.5}{0.189 \times 290}\\m_{(cyl)_1}=1.82 kg$

The mass after the process is

$m_{(cyl)_2}=m_{(cyl)_1}+m\\m_{(cyl)_2}=1.82+1\\m_{(cyl)_2}=2.82\\$

Now the volume 2 of the cylinder is given as

$V_{(cyl)_2}=\frac{m_{(cyl)_2}RT}{P_2}\\m_{(cyl)_2}=\frac{2.82\times 0.189\times 290}{200}\\m_{(cyl)_1}=0.774 m^3$

Part a:

So the Work done is given as

$W=P(V_2-V_1)\\W=200(0.774-0.5)\\W=54.81 kJ$

The total amount of energy transfer by the work done is 54.81 kJ.

Part b:

The total energy transfer by heat is given as

$Q=\Delta U+W\\Q=0+W\\Q=54.81 kJ$

As the temperature is constant thus change in internal energy is 0.

The total amount of energy transfer by the heat is 54.81 kJ

7 0

3 years ago

Please help!!!! Write 5 harmful effects of friction.

zmey [24]

_____ _____hello mate_______

here are five harmful effects of friction

1) It makes us use more fuel

2) The gears in your care will wear down if not lubricated with oil

3) The friction up the device so, due to heating machine can damaged

4) Causes the production of heat between surfaces when the object move
eg : car brakes and tyres heat up due friction

5) Even our shoes wear out due to friction with the ground ; Friction with air causes air craft , meteors to heat

HOPE THE ANSWER WILL HELP U!!!! :-) :-) :-)

:-) :-)

8 0

3 years ago

A friend says that astronauts in orbit are weightless because they are beyond the pull of earths gravity. Correct your friends i

OLga [1]

They might feel weightless and that it depends on which planet they are, they might seem lighter in other planets and heavier on other planets.

4 0

3 years ago

A rectangular loop of wire that can rotate about an axis through its center is placed between the poles of a magnet in a magneti

Afina-wow [57]

Explanation:

hope this helps you...........

3 0

4 years ago

A rocket is launched from a height of 3 m with an initial velocity of 15 m/s What is the maximum height of the rocket? When will

Fudgin [204]

If no extra acceleration is added to the rocket, then its velocity at time t is

v = 15 m/s - g t

where g = 9.80 m/s² is the magnitude of the acceleration due to gravity.

Also, recall that

v² - u² = 2 a ∆x

where u is initial speed, v is final speed, a is acceleration, and ∆x is net displacement.

At the rocket's maximum height ∆x, the velocity is 0. So, the maximum height is

0² - (15 m/s)² = 2 (-g) ∆x

∆x = (15 m/s)² / (2 * (9.80 m/s²)) ≈ 11.48 m

But this assumes the rocket is launched from the ground. We're given that the rocket is launced from 3 m above the ground, so we need to add this to the height above. So the maximum height is closer to 14.48 m.

As mentioned before, this happens when vertical velocity is 0:

0 = 15 m/s - g t

t = (15 m/s) / (9.80 m/s²) ≈ 1.53 s

5 0

3 years ago