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3 years ago

How many laws does newton have?

Physics

1 answer:

liq [111]3 years ago

3 0

Newton has 3 Laws specifically The Three Laws of Motion

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A sound having a frequency of 395 Hz travels through air at 331 m/s. What is the wavelength of the sound? Answer in units of m.

jenyasd209 [6]

Here this should help you out brother I just want to get more

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3 years ago

Calculate the magnitude of the angular momentum of the earth due its daily rotation about its own axis

ioda

$L=Iw$
$I_{earth} = \frac{2}{5} r^{2}m= \frac{2}{5} (6371000^2m)(5.97*10^{24}kg)=9.71*10^ {37}$
$L_{earth}=Iw=(9.71*10^ {37})(7.27*10^{-5})=7.07*10^{33}$ <span>[/tex]</span>

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2 years ago

A 55 kg roller skater is at rest on a flat skating rink, a 198 N horizontal force is needed to set the skater in motion.

Rufina [12.5K]

Answer:

Explanation:

To get the person Moving you have to overcome the static (means not moving) friction coefficient. U(static)

To get the person going at the same speed you have to overcome the kinetic friction coefficient. U(Kinetic)

Force to get him moving is 198 N. Force = ma = U(static)Mg

combining the 2 equations you get 198N = U(static)* 55kg *9.8m/s^2 Solve for U(static)

Same equation to keep him moving except with the dynamic force and the dynamic U

175N= U(kinetic)*55kg*9.8m/s^2 Solve (U dynamic)

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2 years ago

A grindstone in the shape of a solid disk with a diameter of 1.0 m and a mass of 50.0 kg, is rotating at 900 rev/min. A tool is

monitta

Answer:

oh for real?

Explanation:

The solubility of glucose at 30°C is

125 g/100 g water. Classify a solution made by adding 550 g of glucose to 400 mL of water at 30°C. Explain your classification, and describe how you could increase the amount of glucose in the solution without adding more glucose.

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2 years ago

A force of 10 N acts on an object with a mass of 10 kg. What is its acceleration? A. 1 m/s2 B. 10 m/s2 C. 2 m/s2 D. 5 m/s2

Akimi4 [234]

The acceleration exerted by the object of mass 10 kg is $\mathbf{1} m / \boldsymbol{s}^{2}$

Answer: Option A

<u>Explanation:</u>

According to Newton’s second law of motion, any external force acting on a body will be directly proportional to the mass of the body as well as acceleration exerted by the body. So, the net external force acting on any object will be equal to the product of mass of the object with acceleration exerted by the object. Thus,

$Force = Mass \times Acceleration$

So,

$Acceleration=\frac{\text {Force}}{\text {Mass}}$

As the force acting on the object is stated as 10 N and the mass of the object is given as 10 kg, then the acceleration will be

$Acceleration =\frac{10 \mathrm{N}}{10 \mathrm{kg}}=1 \mathrm{m} / \mathrm{s}^{2}$

So, the acceleration exerted by the object of mass 10 kg is $\mathbf{1} m / \boldsymbol{s}^{2}$

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2 years ago