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MAXImum [283]
3 years ago
12

Consider the possible scenarios and determine which of them are true for positive feedbacks or negative feedbacks.A. Increased p

lant photosynthesis resulting from a temperature rise can remove carbon dioxide from the atmosphere which can potentially lead to positive feedback. B. Increased evaporation resulting from a temperature rise can produce more clouds which can potentially lead to a negative feedback. C. Increased plant photosynthesis resulting from a temperature rise can remove carbon dioxide from the atmosphere which can potentially lead to a negative feedback. D. Increased evaporation resulting from a temperature rise can produce more clouds which can potentially lead to a positive feedback. E. If ice cover melts due to a temperature rise the result will be decreased albedo or reflectivity which can potentially lead to a negative feedback. F. If ice cover melts due to a temperature rise the result will be decreased albedo or reflectivity which can potentially lead to a positive
Physics
1 answer:
avanturin [10]3 years ago
5 0

Answer:

Scenario A, B and E is True.

Explanation:

Scenario A) True. Removing carbon dioxide from atmosphere decreases greenhouse effect of atmosphere. Thus, temperature rise decreases.

Scenario B) True. The more evaporation creates the more greenhouse effect. Therefore, temperature rise increases.

Scenario C) False. Removing carbon dioxide from atmosphere decreases greenhouse effect of atmosphere. Thus, temperature rise decreases.

Scenario D) False. The more evaporation creates the more greenhouse effect. Therefore, temperature rise increases.

Scenario E) True. If reflected radiation increases from Earth, temperature rise of the Earth will decrease. Ice cover increases reflectivity which leads temperature level decrease.

Scenario F) False. If reflected radiation increases from Earth, temperature rise of the Earth will decrease. Ice cover increases reflectivity which leads temperature level decrease.

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5500000 millimeters

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1 year ago
What is the acceleration of the the object during the first 4 seconds?
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Answer:

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

Explanation:

What this formula is telling us is that if we know the acceleration of an object, and the ... we can plug in our acceleration of 12.5 m/s2 for a, and 4 seconds for t.

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

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2 years ago
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