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3 years ago

What is the mass of a steel cylinder that has a density of 75.0 g/ml and a volume of 12 ml?

1 answer:

3 0

Density can be calculated using the following rule:
Density = mass / volume

Therefore:
mass = density * volume

We are given that:
Density = 75 g/ml
volume = 12 ml

Substitute with these givens in the equation to get the mass as follows:
mass = density * volume
mass = 75 * 12
mass = 900 g

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BRIANLIESTTT ASAP!!! PLEASE HELP ME :)

Genrish500 [490]

Answer:

Its reliability is confirmed by many scientists

Explanation:

The science and the pseudoscience have multiple differences that separate them clearly and sharply. The science, doesn't matter about scientific field we are talking about, is confirmed by numerous scientists. In order for something to be accepted in the scientific circles as a science, the particular thing in question undergoes numerous studies, from numerous different scientists or scientific groups. If all of the results of all of the studies are confirming the same thing, that it can be accepted as science.

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Consider the reaction below for which K = 78.2 atm-1. A(g) + B(g) ↔ C(g) Assume that 0.386 mol C(g) is placed in the cylinder re

borishaifa [10]

Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

A + B ⇄ C

where;

numbers of moles = 0.386 mol C (g)

Volume = 7.29 L

Molar concentration of C = $\frac{0.386}{7.29}$

= 0.053 M

A + B ⇄ C

Initial 0 0 0.530

Change +x +x - x

Equilibrium x x (0.0530 - x)

$K = \frac{[C]}{[A][B]}$

where

K is given as ; 78.2 atm-1.

So, we have:

$78.2=\frac{[0.0530-x]}{[x][x]}$

$78.2= \frac{(0.0530-x)}{(x^2)}$

$78.2x^2= 0.0530-x$

$78.2x^2+x-0.0530=0$

Using quadratic formula;

$\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where; a = 78.2 ; b = 1 ; c= - 0.0530

= $\frac{-b+\sqrt{b^2-4ac} }{2a}$ or $\frac{-b-\sqrt{b^2-4ac} }{2a}$

= $\frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}$ or $\frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}$

= 0.0204 or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

= 0.0530 - 0.0204

= 0.0326

Total number of moles at equilibrium = 0.0204 + 0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

$V = \frac{nRT}{P}$

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K (fixed constant temperature )

V (volume) = ???

$V=\frac{(0.0734*0.0821*273.15)}{(1.00)}$

V = 1.64604

V ≅ 1.65 L

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3 years ago

Which of the following is a double replacement reaction? Ca(OH)2 + H2SO4 → CaSO4 + 2H2O CH4 + 2O2 → CO2 + 2H2O 8Fe + S8 → 8FeS Z

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That would be the first option Ca(OH)2 + H2SO4 → CaSO4 + 2H2O.

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